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If m angle B=45 of triangle ABC,then(1 cotA)(1 cotC)=? 1)0 2)1 3)-1 4)2?
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If m angle B=45 of triangle ABC,then(1 cotA)(1 cotC)=? 1)0 2)1 3)-1 ...
Solution:

Given, angle B = 45° in triangle ABC.

We know that the sum of all angles in a triangle is 180°.

Therefore, angle A + angle B + angle C = 180°.

Substituting angle B = 45°, we get:

angle A + 45° + angle C = 180°

angle A + angle C = 135°

Now, we need to find the value of (1/cot A) (1/cot C).

Let us first simplify this expression.

(1/cot A) (1/cot C) = (1/tan A) (1/tan C) [Since cot A = 1/tan A and cot C = 1/tan C]

= 1/(tan A tan C)

We know that tan (A + C) = (tan A + tan C)/(1 - tan A tan C)

Substituting angle A + angle C = 135°, we get:

tan 135° = (tan A + tan C)/(1 - tan A tan C)

Since tan 135° = -1, we can write:

-1 = (tan A + tan C)/(1 - tan A tan C)

Simplifying this equation, we get:

tan A tan C + tan A + tan C + 1 = 0

Now, let us try to find the value of (1/cot A) (1/cot C) using the given equation.

(1/cot A) (1/cot C) = (1/tan A) (1/tan C)

= 1/(tan A tan C)

= -1/(tan A + tan C + 1)

We know that tan A + tan C + 1 = -tan A tan C.

Therefore, (1/cot A) (1/cot C) = -1/(-tan A tan C) = 1

Hence, the value of (1/cot A) (1/cot C) is 1.

Therefore, the correct option is 2) 1.

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Community Answer
If m angle B=45 of triangle ABC,then(1 cotA)(1 cotC)=? 1)0 2)1 3)-1 ...
Option b
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