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Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared
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the Class 12 exam syllabus. Information about Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Aluminium oxide may be electrolysed at 1000ºC to furnish aluminium metal (At. Mass=27 amu ; 1 Faraday = 96,500 Coulombs). The cathode reaction isAl3++ 3e-→AlºTo prepare 5.12 kg of aluminium metal by this method would require - [AIEEE-2005]a)1.83 × 107C of electricityb)5.49 × 107C of electricityc)5.49 × 101C of electricityd)5.49 × 104C of electricityCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.