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Let y(x) be the solution of the initial value problem 
Find the value of 
(Correct up to 2 decimal places).
Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer?
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Let y(x) be the solution of the initial value problem Find the value o...
Find PI = e raise to integration of 2x.dx .. Ans of PI is e^ (x^2) ..now y.PI = Integration of x.PI ..so now..we have
y * e^ (x^2) = integration of X * e^ (x^2) dx
Now for integration portion..we can take x^2 = t So 2x.dx = dt
For integration part..multiply and divide by 2
Now we have , y * e^ (x^2) =(1/2) Integration e^t dt =(1/2) e^t + c Put value of t.. =(1/2) e^ (x^2) + c ......(1)
We have initial value of y(0) = 0..for find "c"
(0) . e^(0) = (1/2) e^(0) + c0 = (1/2) + cc = (-1/2)
Put this value in main eq..(1)
y * e^ (x^2) = (1/2) e^ (x^2) - (1/2)
y(x) = [ e^ (x^2) - 1] / 2 * e^ (x^2)
Now put x=1.. y = (e -1) / 2e .... e = 2.72
y = 0.316 ....ANS
y * e^ (x^2) = integration of X * e^ (x^2) dx
Now for integration portion..we can take x^2 = t So 2x.dx = dt
For integration part..multiply and divide by 2
Now we have , y * e^ (x^2) =(1/2) Integration e^t dt =(1/2) e^t + c Put value of t.. =(1/2) e^ (x^2) + c ......(1)
We have initial value of y(0) = 0..for find "c"
(0) . e^(0) = (1/2) e^(0) + c0 = (1/2) + cc = (-1/2)
Put this value in main eq..(1)
y * e^ (x^2) = (1/2) e^ (x^2) - (1/2)
y(x) = [ e^ (x^2) - 1] / 2 * e^ (x^2)
Now put x=1.. y = (e -1) / 2e .... e = 2.72
y = 0.316 ....ANS
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Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer?
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Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer?.
Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let y(x) be the solution of the initial value problem Find the value of (Correct up to 2 decimal places).Correct answer is between '0.31,0.32'. Can you explain this answer?.
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