Find the minimum of capacitor of 2 microfarad required to obtain a capacitance of 5 microfarad.?

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4..I.e. first two capacitor are connected in series ..then1/Cs=1/C1+1/C2.1/Cs=1/2+1/2.Cs=1.------(1)and then,two capacitors in parallel.Cp=C1+C2.Cp=2+2.Cp=4.-----(2).as both (1&2) are joined in a circuit....then they are in parallel combination.. and hence we get ...Cp=4+1=5 micro farad...Hence, 4 capacitors of each 2 microfarad are required to obtain a capacitance of 5 microfarad....

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