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Length, diameter and specific resistance of two wires of different materials are each in the ratio of 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of the other wire?
Most Upvoted Answer
Length, diameter and specific resistance of two wires of different mat...
R=rl /A where r= specific resistance
ratio=2:1
R1=r1*l1/A1
R2=r2*l2/A2
R1/R2=(r1*l1*A2)/(r2*l2*A1)
diameter is in ratio 2:1=>radii are also in ratio 2:1
A1=πr1^2
A2 =πr2^2
So, R1/R2=(r1/r2)*(l1/l2)*(A2/A1)
= 2*2*(1/2)^2
=1
So R1=R2=10 ohm
Community Answer
Length, diameter and specific resistance of two wires of different mat...
Given:
- The ratio of length, diameter, and specific resistance of two wires is 2:1.
- The resistance of one wire is 10 ohm.

To find:
- The resistance of the other wire.

Explanation:
To solve this problem, we need to understand the relationship between the resistance, length, diameter, and specific resistance of a wire.

1. Resistance:
Resistance is a property of a wire that opposes the flow of electric current. It is denoted by the symbol "R" and measured in ohms (Ω).

2. Length:
The length of a wire is the linear distance between its two ends. It is denoted by the symbol "L" and measured in meters (m).

3. Diameter:
The diameter of a wire is the width of its cross-section. It is denoted by the symbol "d" and measured in meters (m).

4. Specific Resistance:
Specific resistance, also known as resistivity, is a property of a material that determines how strongly it resists the flow of electric current. It is denoted by the symbol "ρ" (rho) and measured in ohm-meters (Ω·m).

The resistance of a wire can be calculated using the formula:

R = (ρ * L) / A

Where:
- R is the resistance of the wire
- ρ is the specific resistance of the material
- L is the length of the wire
- A is the cross-sectional area of the wire

Solution:
Let's assume the resistance of the other wire is "R2".

From the given information, we know that the ratio of length (L1:L2), diameter (d1:d2), and specific resistance (ρ1:ρ2) of the two wires is 2:1.

Let's assign the following values:
- L1 = 2x (length of the first wire)
- L2 = x (length of the second wire)
- d1 = 2y (diameter of the first wire)
- d2 = y (diameter of the second wire)
- ρ1 = 2z (specific resistance of the first wire)
- ρ2 = z (specific resistance of the second wire)

We are given that the resistance of the first wire is 10 ohms, so we can write the equation:

R1 = (ρ1 * L1) / A1 = 10

Substituting the values, we get:

(2z * 2x) / (π * (2y/2)^2) = 10
(4zx) / (π * y^2) = 10

Simplifying the equation, we get:

zx / (π * y^2) = 2.5

Now, let's find the resistance of the second wire (R2) using the same formula:

R2 = (ρ2 * L2) / A2

Substituting the values, we get:

(z * x) / (π * (y/2)^2) = R2

Since we want to find the resistance of the second wire (R2), we need to find the value of (z * x)
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Length, diameter and specific resistance of two wires of different materials are each in the ratio of 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of the other wire?
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Length, diameter and specific resistance of two wires of different materials are each in the ratio of 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of the other wire? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Length, diameter and specific resistance of two wires of different materials are each in the ratio of 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of the other wire? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Length, diameter and specific resistance of two wires of different materials are each in the ratio of 2:1. One of the wires has a resistance of 10 ohm. Find the resistance of the other wire?.
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