K2Cr2O7 is an oxidising agent in acidic medium. How many O-atoms are directly linked to each Cr-atom?Correct answer is '4'. Can you explain this answer?

Question

Answer

Potassium dichromate, K 2Cr 2O 7, is a common inorganic chemical reagent, most commonly used as an oxidizing agent in various laboratory and industrial applications.

Potassium Dichromate molecules feature two ionic bonds between the two positively charged potassium cations and the dichromate anion, which holds a charge of -2. The dichromate ion features two chromium atoms that are bonded to four different oxygen atoms. Two of these Cr-O bonds are double bonds and one of the oxygen atoms is bonded to both the chromium atoms. The last oxygen atoms that are singly bonded to the chromium atom hold a charge of -1 .

Hence 4 is the right answer.

Answer

Answer

Oxidation state of Cr in K2Cr2O7
- First, we need to determine the oxidation state of Cr in K2Cr2O7.
- Oxygen has an oxidation state of -2 and the molecule has a net charge of -2, so the total oxidation state of the oxygen atoms in K2Cr2O7 is -14.
- The two potassium ions have a combined oxidation state of +2, so the oxidation state of the two Cr atoms must be +12.
- Each Cr atom is therefore in the +6 oxidation state.

O-atoms directly linked to each Cr-atom
- In K2Cr2O7, each Cr atom is surrounded by four oxygen atoms.
- These oxygen atoms are directly linked to the Cr atom through double bonds.
- Therefore, each Cr atom is directly linked to four O atoms.

Conclusion
- The correct answer to the question 'How many O-atoms are directly linked to each Cr-atom in K2Cr2O7?' is 4.
- This is because each Cr atom is surrounded by four oxygen atoms, which are directly linked to the Cr atom through double bonds.

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