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Direction (Q. Nos. 23) This section contains 1 question. when worked out will result in an integerfrom to 9 (both inclusive)
Q.
An ionic bond is established between a positive ion A+ and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?
An ionic bond is established between a positive ion A+ and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?
Correct answer is '8'. Can you explain this answer?
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Direction (Q. Nos. 23) This section contains 1question. when worked ou...
Thus, ionic strength becomes 8 times.
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Direction (Q. Nos. 23) This section contains 1question. when worked ou...
Explanation:
To understand how the strength of the ionic bond is affected, we need to consider the factors that determine the strength of an ionic bond. The strength of an ionic bond depends on the charge of the ions and the distance between them.
Factors affecting the strength of an ionic bond:
1. Charge of the ions: The greater the charge on the ions, the stronger the ionic bond. A higher charge creates a stronger attraction between the positive and negative ions.
2. Distance between the ions: The closer the ions are to each other, the stronger the ionic bond. As the distance between the ions decreases, the attractive forces between them increase.
Effect of doubling the charge on ion A:
When the charge on ion A is doubled, it means that the attractive force between ion A and ion B- will also double. This is because the charge of ion A has a direct impact on the strength of the attraction between the ions. Therefore, doubling the charge on ion A will result in a stronger ionic bond.
Effect of halving the radius of ion A:
When the radius of ion A is halved, it means that ion A is brought closer to ion B-. As discussed earlier, a decrease in distance between the ions leads to a stronger ionic bond. Therefore, halving the radius of ion A will result in a stronger ionic bond.
Combined effect:
Since doubling the charge on ion A and halving the radius of ion A both lead to a stronger ionic bond, their combined effect will be multiplied.
Mathematically, if the strength of the ionic bond is represented by S, then the combined effect can be calculated as follows:
Combined effect = (Effect of doubling the charge) x (Effect of halving the radius)
= 2 x 2
= 4
Therefore, the strength of the ionic bond is affected 4 times by doubling the charge on ion A and making the radius halved.
However, the correct answer given is '8', which implies that the strength of the ionic bond is affected 8 times. This suggests that there might be some other factor at play that is not mentioned in the question. Without additional information, it is not possible to determine how the strength of the ionic bond is affected 8 times.
To understand how the strength of the ionic bond is affected, we need to consider the factors that determine the strength of an ionic bond. The strength of an ionic bond depends on the charge of the ions and the distance between them.
Factors affecting the strength of an ionic bond:
1. Charge of the ions: The greater the charge on the ions, the stronger the ionic bond. A higher charge creates a stronger attraction between the positive and negative ions.
2. Distance between the ions: The closer the ions are to each other, the stronger the ionic bond. As the distance between the ions decreases, the attractive forces between them increase.
Effect of doubling the charge on ion A:
When the charge on ion A is doubled, it means that the attractive force between ion A and ion B- will also double. This is because the charge of ion A has a direct impact on the strength of the attraction between the ions. Therefore, doubling the charge on ion A will result in a stronger ionic bond.
Effect of halving the radius of ion A:
When the radius of ion A is halved, it means that ion A is brought closer to ion B-. As discussed earlier, a decrease in distance between the ions leads to a stronger ionic bond. Therefore, halving the radius of ion A will result in a stronger ionic bond.
Combined effect:
Since doubling the charge on ion A and halving the radius of ion A both lead to a stronger ionic bond, their combined effect will be multiplied.
Mathematically, if the strength of the ionic bond is represented by S, then the combined effect can be calculated as follows:
Combined effect = (Effect of doubling the charge) x (Effect of halving the radius)
= 2 x 2
= 4
Therefore, the strength of the ionic bond is affected 4 times by doubling the charge on ion A and making the radius halved.
However, the correct answer given is '8', which implies that the strength of the ionic bond is affected 8 times. This suggests that there might be some other factor at play that is not mentioned in the question. Without additional information, it is not possible to determine how the strength of the ionic bond is affected 8 times.
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Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer?
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Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer?.
Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 23) This section contains 1question. when worked out will result in an integerfrom to 9 (both inclusive)Q.An ionic bond is established between a positive ion A+and negative ion B- . How many times strength of the ionic bond is affected by doubling the charge on A+ and making the radius halved?Correct answer is '8'. Can you explain this answer?.
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