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In BF3BF3, molecule below the dipole moment is zero although the B- F bonds are oriented at an angle of 1200 to one another. Net dipole moment in BF3, molecule is
  • a)
    three
  • b)
    two
  • c)
    zero
  • d)
    one
Correct answer is option 'C'. Can you explain this answer?
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InBF3BF3, molecule below the dipole moment is zero although the B- F b...
In BF3, molecule above the dipole moment is zero because the B- F bonds are oriented at an angle of 1200 to one another so net dipole cancel out.
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InBF3BF3, molecule below the dipole moment is zero although the B- F b...
Explanation:

BF3 is a trigonal planar molecule with a central boron atom surrounded by three fluorine atoms. The B-F bonds are arranged at an angle of 120 degrees to each other around the central boron atom. The dipole moment of a molecule is the measure of its polarity, which is the product of the magnitude of the charge and the distance between the charges. In a polar molecule, the dipole moment is non-zero. In a non-polar molecule, the dipole moment is zero.

Symmetry of BF3 molecule:
The BF3 molecule has a trigonal planar geometry. It has a symmetrical shape, and the three B-F bonds are arranged in a plane around the central boron atom. Since the three B-F bonds are identical and arranged symmetrically around the central boron atom, the dipole moments of the individual B-F bonds cancel out each other and the net dipole moment of the molecule becomes zero.

Electronegativity:
The electronegativity of boron is 2.04, and the electronegativity of fluorine is 3.98. The difference in electronegativity between boron and fluorine is 1.94, which indicates that the B-F bond is polar. However, the symmetry of the BF3 molecule cancels out the dipole moments of the individual B-F bonds, resulting in a non-polar molecule with a net dipole moment equal to zero.

Conclusion:
In BF3, the dipole moment is zero because the individual dipole moments of the B-F bonds cancel out each other due to the symmetrical arrangement of the molecule. Therefore, option 'C' is the correct answer.
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InBF3BF3, molecule below the dipole moment is zero although the B- F bonds are oriented at an angle of1200to one another. Net dipole moment in BF3, molecule isa)threeb)twoc)zerod)oneCorrect answer is option 'C'. Can you explain this answer?
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