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A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, L mm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal to
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A capillary tube of uniform diameter contains gas samples A and B, sep...
By ideal gas law: PV=nRT
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
Most Upvoted Answer
A capillary tube of uniform diameter contains gas samples A and B, sep...
By ideal gas law: PV=nRT
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
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Community Answer
A capillary tube of uniform diameter contains gas samples A and B, sep...
By ideal gas law: PV=nRT
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
For a particular gas since n and T are constant. ⇒PV=Constant
⇒ For gas A
Pa=PAa′..............(i) (Here length (a) is directly proportional to volume. Hence it can be used in place of volume.)
⇒ For gas B
Pb=PBb′.......(ii)
Since gas B is supporting l length of mercury over it in addition to gas A
⇒PB=PA+ρgl..........(iii) ( ρ is the density of mercury)
Putting (iii) in (ii)
⇒Pb=(PA+ρgl)b′............(iv)
Eliminating PA
from (i) and (iv)
⇒Pb=Pa/a′b′+ρglb′⇒Pba′−ab′)/a’=ρglb′
⇒P=ρgla′b′/ba’-ab’(in SI units)
⇒P in mm of Hg =dP(in SI)/ρg
P(mmHg)=la′b′/ba′-ab′ = l/(b/b′) - (a/a′)
Thus (a) is the correct option
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A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer?.
A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer?.
Solutions for A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A capillary tube of uniform diameter contains gas samples A and B, separated by a short column of Hg, Lmm in length. The ends are sealed. In horizontal position, the confined gases occupy 'a' mm and 'b' mm in length with a common unknown pressure (P). In vertical position, the lengths become respectively a' mm and b' mm. Then P is equal toa)b)c)d)Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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