Class 11 Exam > Class 11 Questions > Reaction involving gold have been of particul...
Start Learning for Free
Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.
Au(OH)3 + 4 HCl → HAuCl4 + 3H2O, ΔH = -28 kcal
Au(OH)3 + 4 HBr → HAuBr4 + 3 H2O, ΔH = -36.8 kcal
In an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4 was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4 into HAuCl4 ?
- a)0.5 %
- b)0.6 %
- c)5 %
- d)50 %
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Reaction involving gold have been of particular interest to a chemist....
Au(OH)3 + 4HCl → HAuCl4+ 3H2O…(1) ∆H₁=-28kcal
Au(OH)3 + 4HBr → HAuBr4 + 3H2O ...(2) ∆H₂= -36.8kcal
To convert HAuBr4 to HAuCl4, the net reaction is
HAuBr4 + 4HCl→ HAuCl4 + 4HBr ...∆H=?
For the above reaction:
∆H =∆H₁ - ∆H₂ = -28 - (-36.8) = 8.8 kcal
Thus to convert one mole of HAuBr4 to HAuCl4 we require 8.8 kcal energy but since the energy absorbed is 0.44 kcal.
hence %conversion =[(0.44)/(8.8)] x 100
= 5%
Hence the percentage conversion is 5%.
Most Upvoted Answer
Reaction involving gold have been of particular interest to a chemist....
The reaction between Au(OH)3 and 4 HCl would result in the formation of gold chloride (AuCl3) and water (H2O). This reaction can be represented by the following balanced chemical equation:
Au(OH)3 + 4 HCl → AuCl3 + 3 H2O
In this reaction, the gold hydroxide (Au(OH)3) reacts with hydrochloric acid (HCl) to form gold chloride (AuCl3) and water (H2O). This type of reaction is called a displacement reaction, where the chloride ions from the hydrochloric acid displace the hydroxide ions from the gold hydroxide, resulting in the formation of gold chloride.
This reaction is of interest to chemists because gold chloride is an important compound in various applications, such as in gold plating, catalysts, and in the synthesis of other gold compounds. Additionally, studying the reactions of gold compounds helps to understand the reactivity and behavior of gold in different chemical environments.
Au(OH)3 + 4 HCl → AuCl3 + 3 H2O
In this reaction, the gold hydroxide (Au(OH)3) reacts with hydrochloric acid (HCl) to form gold chloride (AuCl3) and water (H2O). This type of reaction is called a displacement reaction, where the chloride ions from the hydrochloric acid displace the hydroxide ions from the gold hydroxide, resulting in the formation of gold chloride.
This reaction is of interest to chemists because gold chloride is an important compound in various applications, such as in gold plating, catalysts, and in the synthesis of other gold compounds. Additionally, studying the reactions of gold compounds helps to understand the reactivity and behavior of gold in different chemical environments.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer?
Question Description
Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer?.
Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer?.
Solutions for Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Reaction involving gold have been of particular interest to a chemist. Consider the following reactions.Au(OH)3+ 4 HCl →HAuCl4+ 3H2O,ΔH = -28 kcalAu(OH)3+ 4 HBr →HAuBr4+ 3 H2O, ΔH = -36.8 kcalIn an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4into HAuCl4?a)0.5 %b)0.6 %c)5 %d)50 %Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup