Class 11 Exam  >  Class 11 Questions  >  A rod PQ of mass m, area of cross section A, ... Start Learning for Free
A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P?
Most Upvoted Answer
A rod PQ of mass m, area of cross section A, length l and young modulu...
To solve this problem we have to cut the rod at a distance of "x" from point P. The main thing here is that even if we cut the rod into two parts (whether equal or not) the acceleration of each part will be same as that of the original rod before cutting. The tension developed here is nothing but the restoring force which is caused due to the elastic nature of the rod. 
Community Answer
A rod PQ of mass m, area of cross section A, length l and young modulu...
**The Problem Setup**

We have a rod PQ of mass m, length l, and cross-sectional area A, lying on a smooth table. A force F is applied at point P on the rod. We need to find the tension at a distance x from point P.

**Understanding the Problem**

To find the tension at distance x from point P, we need to analyze the forces acting on the rod. The applied force F will create a tension force at point P, which will be transmitted along the rod. At any point on the rod, there will be two forces acting: the tension force from the left side and the tension force from the right side. We need to find the magnitude of the tension force at point x.

**Analysis of Forces**

Let's consider a small section of the rod between points P and x. This section has a length dx and a mass dm. The force F applied at point P will create a tension force T at point P, which will be transmitted along the rod.

**Tension Force Calculation**

To calculate the tension force at point x, we can consider the equilibrium of forces for the small section of the rod between points P and x.

The tension force at point P can be written as:
T = F

The tension force at point x can be written as:
T + dT = Tension force from the right side

Since the rod is in equilibrium, the sum of forces acting on the small section should be zero.

**Sum of Forces**

The sum of forces acting on the small section of the rod can be written as:
dT - T = 0

Simplifying the equation, we get:
dT = T

**Integration to Find Tension**

To find the tension force at point x, we need to integrate the equation dT = T over the length of the rod.

∫ dT = ∫ T

Integrating both sides, we get:
T - T0 = ∫ T dx

T - T0 = ∫ F dx

T - T0 = Fx

Therefore, the tension force at a distance x from point P can be calculated as:
T = T0 + Fx

**Conclusion**

In conclusion, the tension force at a distance x from point P on the rod is given by the equation T = T0 + Fx, where T0 is the tension at point P and F is the applied force at point P. This equation is derived by analyzing the forces acting on a small section of the rod and considering the equilibrium of forces.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
Explore Courses for Class 11 exam

Similar Class 11 Doubts

Attempt All Questions sub parts from each question.Elasticity vs. plasticity: Objects get deformed when pushed, pulled, and twisted. Elasticity is the measure of the amount that the object can return to its original shape after these external forces and pressure are removed. The opposite of elasticity is plasticity. When something is stretched, and it stays stretched, the material is said to be plastic. Such deformation is said to be plastic deformation. In elastic deformation, atoms of the material are displaced temporarily from their original lattice site. They return back to their original position after the removal of external force. In plastic deformation, atoms of the solid are displaced permanently from their original lattice site. They don’t return back to the original position even after the removal of external load. So, elastic deformation is temporary, whereas plastic deformation is permanent. Amount of elastic deformation is very small. But the amount of plastic deformation is quite large. External force required for elastic deformation of solid is quite small. Force required for plastic deformation is much higher. Total energy absorbed by the material during elastic and plastic deformation region is called modulus of toughness. Energy absorbed by the material during elastic deformation is called module of resilience. Most materials have an amount of force or pressure for which they deform elastically. If more force or pressure is applied, then they undergo plastic deformation. Materials those have a fair amount of plastic deformation before breaking are said to be ductile. Materials those can't stretch or bend much without breaking are said to be brittle. Copper, aluminium etc. are ductile materials. For this reason those are used for making wires. Glass and ceramics are often brittle; they will not bend; they will break.Q. Which of the following statement is false?

Attempt All Questions sub parts from each question.Elasticity vs. plasticity: Objects get deformed when pushed, pulled, and twisted. Elasticity is the measure of the amount that the object can return to its original shape after these external forces and pressure are removed. The opposite of elasticity is plasticity. When something is stretched, and it stays stretched, the material is said to be plastic. Such deformation is said to be plastic deformation. In elastic deformation, atoms of the material are displaced temporarily from their original lattice site. They return back to their original position after the removal of external force. In plastic deformation, atoms of the solid are displaced permanently from their original lattice site. They don’t return back to the original position even after the removal of external load. So, elastic deformation is temporary, whereas plastic deformation is permanent. Amount of elastic deformation is very small. But the amount of plastic deformation is quite large. External force required for elastic deformation of solid is quite small. Force required for plastic deformation is much higher. Total energy absorbed by the material during elastic and plastic deformation region is called modulus of toughness. Energy absorbed by the material during elastic deformation is called module of resilience. Most materials have an amount of force or pressure for which they deform elastically. If more force or pressure is applied, then they undergo plastic deformation. Materials those have a fair amount of plastic deformation before breaking are said to be ductile. Materials those can't stretch or bend much without breaking are said to be brittle. Copper, aluminium etc. are ductile materials. For this reason those are used for making wires. Glass and ceramics are often brittle; they will not bend; they will break.Q. Aluminium is a ............... materials.

Top Courses for Class 11

A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P?
Question Description
A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P?.
Solutions for A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? defined & explained in the simplest way possible. Besides giving the explanation of A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P?, a detailed solution for A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? has been provided alongside types of A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? theory, EduRev gives you an ample number of questions to practice A rod PQ of mass m, area of cross section A, length l and young modulus of elasticity Y is lying on a smooth table. a force F is applied at P. find tension at a distance x from end P? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev