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Direction (Q. Nos. 21) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive)
Q. For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, 
When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc is
When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc is
Correct answer is '4'. Can you explain this answer?
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Verified Answer
Direction (Q. Nos. 21) This section contains 2questions. when worked o...
The correct answer is 4
2SO2(g) + O2(g) ⇋ 2SO3
Initial moles 2 1
At equilibrium 2 - 2x 1 - x 2x
Net moles at equilibrium = 2 - 2x + 1 - x + 2x
=(3 - x)moles
Initial:
moles = 3,
Pressure = 3 atm,
Volume = 2L,
PV = nRT
3 x 2 = 3RT -------- 1
At equilibrium
Moles = 3 - x,
Pressure = 2.5 atm
Volume = 2L
P‘V = n’RT ---------- 2
Divide eqn 2 by 1
⇒2.5 = 3 - x
⇒x = 0.5
2SO2(g) + O2(g) ⇋ 2SO3
Initial moles 2 1
At equilibrium 2 - 2x 1 - x 2x
Net moles at equilibrium = 2 - 2x + 1 - x + 2x
=(3 - x)moles
Initial:
moles = 3,
Pressure = 3 atm,
Volume = 2L,
PV = nRT
3 x 2 = 3RT -------- 1
At equilibrium
Moles = 3 - x,
Pressure = 2.5 atm
Volume = 2L
P‘V = n’RT ---------- 2
Divide eqn 2 by 1
⇒2.5 = 3 - x
⇒x = 0.5
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Direction (Q. Nos. 21) This section contains 2questions. when worked o...
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Direction (Q. Nos. 21) This section contains 2questions. when worked o...
The correct answer is 4
2SO2(g) + O2(g) ⇋ 2SO3
Initial moles 2 1
At equilibrium 2 - 2x 1 - x 2x
Net moles at equilibrium = 2 - 2x + 1 - x + 2x
=(3 - x)moles
Initial:
moles = 3,
Pressure = 3 atm,
Volume = 2L,
PV = nRT
3 x 2 = 3RT -------- 1
At equilibrium
Moles = 3 - x,
Pressure = 2.5 atm
Volume = 2L
P‘V = n’RT ---------- 2
Divide eqn 2 by 1
⇒2.5 = 3 - x
⇒x = 0.5
2SO2(g) + O2(g) ⇋ 2SO3
Initial moles 2 1
At equilibrium 2 - 2x 1 - x 2x
Net moles at equilibrium = 2 - 2x + 1 - x + 2x
=(3 - x)moles
Initial:
moles = 3,
Pressure = 3 atm,
Volume = 2L,
PV = nRT
3 x 2 = 3RT -------- 1
At equilibrium
Moles = 3 - x,
Pressure = 2.5 atm
Volume = 2L
P‘V = n’RT ---------- 2
Divide eqn 2 by 1
⇒2.5 = 3 - x
⇒x = 0.5
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Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer?
Question Description
Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer?.
Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer?, a detailed solution for Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? has been provided alongside types of Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Direction (Q. Nos. 21) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For the equilibrium in gaseous phase in 2 L flask we start with 2 moles of SO2 and 1 mole of O2 at 3 atm, When equilibrium is attained, pressure changes to 2.5 atm. Hence, equilibrium constant Kc isCorrect answer is '4'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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