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Direction (Q. Nos. 21) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.
The progress of the reaction 
with time t is shown below.
Match the parameters in Column l with their respective values in Column II.
Codes
with time t is shown below.Match the parameters in Column l with their respective values in Column II.
Codes
- a)a
- b)b
- c)c
- d)d
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Direction (Q. Nos. 21) Choice the correct combination of elements and ...
The correct answer is Option A.
Loss in concentration of A in I hour = 
= 0.1
Gain in concentration of B in I hour =
0.2
(i) ∵0.1 mole of A changes to 0.2 mole of B in a given time and thus, n=2
(ii) Equilibrium constant,
= 1.2mollitre−1
(iii) Initial rate of conversion of A = changes in conc. of A during I hour =
= 0.1 mol litre−1hour−1
(iv) ∵ Equilibrium is attained after 5 hr, where [B]=0.6 and [A]=0.3
= 0.1Gain in concentration of B in I hour =
0.2(i) ∵0.1 mole of A changes to 0.2 mole of B in a given time and thus, n=2
(ii) Equilibrium constant,
= 1.2mollitre−1(iii) Initial rate of conversion of A = changes in conc. of A during I hour =
= 0.1 mol litre−1hour−1
(iv) ∵ Equilibrium is attained after 5 hr, where [B]=0.6 and [A]=0.3
Most Upvoted Answer
Direction (Q. Nos. 21) Choice the correct combination of elements and ...
As final curve of a reaches to 0.6 so conc of b is it and n is 0.1 as it changes from time in 1 second
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Community Answer
Direction (Q. Nos. 21) Choice the correct combination of elements and ...
The correct answer is Option A.
Loss in concentration of A in I hour = = 0.1
Gain in concentration of B in I hour =0.2
(i) ∵0.1 mole of A changes to 0.2 mole of B in a given time and thus, n=2
(ii) Equilibrium constant,
= 1.2mollitre−1
(iii) Initial rate of conversion of A = changes in conc. of A during I hour =
= 0.1 mol litre−1hour−1
(iv) ∵ Equilibrium is attained after 5 hr, where [B]=0.6 and [A]=0.3
= 0.1Gain in concentration of B in I hour =
0.2(i) ∵0.1 mole of A changes to 0.2 mole of B in a given time and thus, n=2
(ii) Equilibrium constant,
= 1.2mollitre−1(iii) Initial rate of conversion of A = changes in conc. of A during I hour =
= 0.1 mol litre−1hour−1
(iv) ∵ Equilibrium is attained after 5 hr, where [B]=0.6 and [A]=0.3
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Direction (Q. Nos. 21) Choice the correct combination of elements and column I and coloumn II are given as option(a), (b), (c) and (d), out of which ONE option is correct.The progress of the reactionwith time t is shown below.Match the parameters in Column l with their respective values in Column II.Codes a)ab)bc)cd)dCorrect answer is option 'A'. Can you explain this answer?
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