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The ionization constant of acetic acid is 1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.
  • a)
    0.00193M and pH 3.03
  • b)
    0.00203M and pH 3.03
  • c)
    0.00093M and pH 3.03
  • d)
    0.00013M and pH 3.03
Correct answer is option 'C'. Can you explain this answer?
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The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer?
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The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer?.
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Here you can find the meaning of The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The ionization constant of acetic acid is1.74 x 10−5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.a)0.00193M and pH 3.03b)0.00203M and pH 3.03c)0.00093M and pH 3.03d)0.00013M and pH 3.03Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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