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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is-   
[AIEEE-2004]
  • a)
    2.5 × 102
  • b)
    50
  • c)
    4 × 10-4
  • d)
    0.02
Correct answer is option 'B'. Can you explain this answer?
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
Kc'= (1/Kc)^1/2
hence,
Kc' = (1/4×10^-4)^1/2
Kc' = (1/2×10^-2)
Kc' = 50
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
The equilibrium constant (K) for the reaction N2(g) + O2(g) ⇌ 2NO(g) at temperature T is 4.

This means that at equilibrium, the concentration of products (NO) is four times higher than the concentration of reactants (N2 and O2). The equilibrium expression for this reaction is:

K = [NO]^2 / [N2] [O2]

Where [NO], [N2], and [O2] represent the molar concentrations of the respective species.

Since K = 4, it implies that at equilibrium, the concentration of NO squared is four times the product of the concentrations of N2 and O2.
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004] a)2.5 × 102b)50c)4 × 10-4d)0.02Correct answer is option 'B'. Can you explain this answer?
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