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The equilibrium constant for the reaction N2(g) + O2(g) 
2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) 
N2(g) + O2(g) at the same temperature is-
2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004]
- a)2.5 × 102
- b)50
- c)4 × 10-4
- d)0.02
Correct answer is option 'B'. Can you explain this answer?
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
Kc'= (1/Kc)^1/2
hence,
Kc' = (1/4×10^-4)^1/2
Kc' = (1/2×10^-2)
Kc' = 50
hence,
Kc' = (1/4×10^-4)^1/2
Kc' = (1/2×10^-2)
Kc' = 50
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at te...
The equilibrium constant (K) for the reaction N2(g) + O2(g) ⇌ 2NO(g) at temperature T is 4.
This means that at equilibrium, the concentration of products (NO) is four times higher than the concentration of reactants (N2 and O2). The equilibrium expression for this reaction is:
K = [NO]^2 / [N2] [O2]
Where [NO], [N2], and [O2] represent the molar concentrations of the respective species.
Since K = 4, it implies that at equilibrium, the concentration of NO squared is four times the product of the concentrations of N2 and O2.
This means that at equilibrium, the concentration of products (NO) is four times higher than the concentration of reactants (N2 and O2). The equilibrium expression for this reaction is:
K = [NO]^2 / [N2] [O2]
Where [NO], [N2], and [O2] represent the molar concentrations of the respective species.
Since K = 4, it implies that at equilibrium, the concentration of NO squared is four times the product of the concentrations of N2 and O2.
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004] a)2.5 × 102b)50c)4 × 10-4d)0.02Correct answer is option 'B'. Can you explain this answer?
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The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004] a)2.5 × 102b)50c)4 × 10-4d)0.02Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004] a)2.5 × 102b)50c)4 × 10-4d)0.02Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant for the reaction N2(g) + O2(g) 2NO(g) at temperature T is 4×10-4. The value of KC for the reaction NO(g) N2(g) + O2(g) at the same temperature is- [AIEEE-2004] a)2.5 × 102b)50c)4 × 10-4d)0.02Correct answer is option 'B'. Can you explain this answer?.
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