One mole of CaOCI2 is dissolved in water and excess of Kl added. Hypo ...
To determine the amount of hypo (Na2S2O3) required to react completely with the oxidized part of CaOCI2, we need to first understand the reaction that takes place between these compounds.
The balanced chemical equation for the reaction between CaOCI2 and hypo (Na2S2O3) is as follows:
CaOCI2 + 2Na2S2O3 → CaS2O3 + 2NaCl + Na2SO4
From the equation, we can see that one mole of CaOCI2 reacts with 2 moles of Na2S2O3. Therefore, the stoichiometric ratio between CaOCI2 and Na2S2O3 is 1:2.
Given that we have one mole of CaOCI2, we can calculate the amount of Na2S2O3 required using the stoichiometric ratio.
Calculation:
1 mole of CaOCI2 reacts with 2 moles of Na2S2O3
Therefore, 1 mole of CaOCI2 requires 2 moles of Na2S2O3.
Thus, the correct answer is option (C) 2 moles of Na2S2O3.
Explanation:
- The balanced chemical equation shows the stoichiometric ratio between CaOCI2 and Na2S2O3.
- By using the stoichiometric ratio, we can determine the amount of Na2S2O3 required to react completely with one mole of CaOCI2.
- The stoichiometric ratio tells us that for every mole of CaOCI2, we need 2 moles of Na2S2O3.
- Therefore, 2 moles of Na2S2O3 are required to completely react with one mole of CaOCI2.
- This is why the correct answer is option (C) 2 moles.