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Direction (Q. Nos. 16-18) This section contains 4 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONE or MORE THANT ONE is correct.
choices (a), (b), (c) and (d), out of which ONE or MORE THANT ONE is correct.
Q. Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,
- a)Cr (III) is formed
- b)Equivalent mass of chromate (VI) = M/3
- c)Equivalent mass of sulphate (IV) =M/2
- d)Oxidation product is sulphate (VI)
Correct answer is option 'A,B,C,D'. Can you explain this answer?
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Direction (Q. Nos. 16-18) This section contains 4multiple choice quest...
Thus, (a) is correct.
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Direction (Q. Nos. 16-18) This section contains 4multiple choice quest...
Explanation:
Chromate (VI) ion reduction by Sulphate (IV) ion:
- Sulphate (IV) ion can reduce chromate (VI) to a green colored salt.
- The reaction can be represented as: Cr2O72- + 3SO32- + 8H+ → 2Cr3+ + 3SO42- + 4H2O
Consequences of the reaction:
- (a) Cr (III) is formed: The chromium (VI) ion is reduced to chromium (III) ion in this reaction.
- (b) Equivalent mass of chromate (VI) = M/3: Since 3 moles of sulphate (IV) ion are required to reduce 1 mole of chromate (VI) ion, the equivalent mass of chromate (VI) would be M/3.
- (c) Equivalent mass of sulphate (IV) = M/2: The equivalent mass of sulphate (IV) can be calculated based on the number of moles of electrons transferred during the reaction, which is half of the molar mass of the ion.
- (d) Oxidation product is sulphate (VI): The oxidation product of sulphate (IV) ion in this reaction is sulphate (VI) ion.
Therefore, all the given options A, B, C, and D are correct in this context.
Chromate (VI) ion reduction by Sulphate (IV) ion:
- Sulphate (IV) ion can reduce chromate (VI) to a green colored salt.
- The reaction can be represented as: Cr2O72- + 3SO32- + 8H+ → 2Cr3+ + 3SO42- + 4H2O
Consequences of the reaction:
- (a) Cr (III) is formed: The chromium (VI) ion is reduced to chromium (III) ion in this reaction.
- (b) Equivalent mass of chromate (VI) = M/3: Since 3 moles of sulphate (IV) ion are required to reduce 1 mole of chromate (VI) ion, the equivalent mass of chromate (VI) would be M/3.
- (c) Equivalent mass of sulphate (IV) = M/2: The equivalent mass of sulphate (IV) can be calculated based on the number of moles of electrons transferred during the reaction, which is half of the molar mass of the ion.
- (d) Oxidation product is sulphate (VI): The oxidation product of sulphate (IV) ion in this reaction is sulphate (VI) ion.
Therefore, all the given options A, B, C, and D are correct in this context.
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Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer?
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Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer?.
Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 16-18) This section contains 4multiple choice questions. Each question has fourchoices (a), (b), (c) and (d), out of whichONE or MORE THANT ONE is correct.Q.Sulphate (IV) ion reduces chromate (VI) to green coloured salt. Thus,a)Cr (III) is formedb)Equivalent mass of chromate (VI) =M/3c)Equivalent mass of sulphate (IV) =M/2d)Oxidation product is sulphate (VI)Correct answer is option 'A,B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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