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One gram is silver salt of an organic dibasic acid yields , on strong heating , 0.5934 g of silver. if the weight percentage of carbon in it 8 times the weight percentage of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid. [Atomic weight of Ag = 108]
  • a)
    C4H6O4
  • b)
    C4H6O6
  • c)
    C2H6O2
  • d)
    C5H10O5
Correct answer is option 'B'. Can you explain this answer?
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One gram is silver salt of an organic dibasicacid yields , on strong h...
Option B is correct answer because H & O will have same number of moles from given composition in the empirical formula. 
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One gram is silver salt of an organic dibasicacid yields , on strong h...
H2A → Ag2A → Ag
Mass of compound = 1 gm
Mass of Ag in compound = 0.5934 gm
Since same mole of Ag be on both sides, 
2 /216+MA = 0.5934/108
Or MA = 148
Therefore molar mass of acid(H2A) = 148+2 = 150gm
Let %age of C = x

Therefore, empirical formula = C2H3O3
(Empirical mass) n = molar mass
n = 150/75 =2
Therefore, molecular formula = C4H6O6
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One gram is silver salt of an organic dibasicacid yields , on strong h...
Given Data:
- Gram of silver salt of an organic dibasic acid yields 0.5934 g of silver
- Weight percentage of carbon is 8 times the weight percentage of hydrogen
- Weight percentage of oxygen is half the weight percentage of hydrogen
- Atomic weight of Ag = 108

Calculations:
1. Calculate the molar mass of the organic dibasic acid:
- The molar mass of Ag = 108 g/mol
- 0.5934 g of Ag is obtained from 1 g of the acid
- Therefore, the molar mass of the acid = (1 / 0.5934) x 108 = 181.85 g/mol
2. Let the molecular formula of the acid be CxHyOz:
- Given weight percentage of carbon = 8 times weight percentage of hydrogen
- Given weight percentage of oxygen = 0.5 times weight percentage of hydrogen
3. Calculate the weight percentages of each element in the acid:
- Let the weight percentage of hydrogen be x%
- Weight percentage of carbon = 8x%
- Weight percentage of oxygen = 0.5x%
4. Use the molar mass and weight percentages to find the molecular formula:
- Molar mass = (x/100)(1) + (8x/100)(12) + (0.5x/100)(16) = 181.85
- Solving for x gives x = 6, y = 6, z = 6

Conclusion:
The molecular formula of the acid is C6H6O6, which corresponds to option B: C4H6O6.
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One gram is silver salt of an organic dibasicacid yields , on strong heating , 0.5934 g of silver. if theweight percentage of carbon in it 8 times the weight percentage of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid. [Atomic weight of Ag = 108]a)C4H6O4b)C4H6O6c)C2H6O2d)C5H10O5Correct answer is option 'B'. Can you explain this answer?
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One gram is silver salt of an organic dibasicacid yields , on strong heating , 0.5934 g of silver. if theweight percentage of carbon in it 8 times the weight percentage of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid. [Atomic weight of Ag = 108]a)C4H6O4b)C4H6O6c)C2H6O2d)C5H10O5Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about One gram is silver salt of an organic dibasicacid yields , on strong heating , 0.5934 g of silver. if theweight percentage of carbon in it 8 times the weight percentage of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid. [Atomic weight of Ag = 108]a)C4H6O4b)C4H6O6c)C2H6O2d)C5H10O5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One gram is silver salt of an organic dibasicacid yields , on strong heating , 0.5934 g of silver. if theweight percentage of carbon in it 8 times the weight percentage of hydrogen and half the weight percentage of oxygen, determine the molecular formula of the acid. [Atomic weight of Ag = 108]a)C4H6O4b)C4H6O6c)C2H6O2d)C5H10O5Correct answer is option 'B'. Can you explain this answer?.
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