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140 cal of heat is required to raise the temperature of 4 mole of an ideal gas at constant pressure from 40 to 45degree Celsius . what is the amount of heat required to raise temperature of same gas through same temperature of constant volume? Ans: 100 cal explain?
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Calculation of Heat Required at Constant Volume

Given:
Heat required at constant pressure (qP) = 140 cal
Temperature change (ΔT) = 45°C - 40°C = 5°C
Number of moles (n) = 4

We need to find the heat required at constant volume (qV) for the same gas.

Formula:
qP = nCpΔT
qV = nCvΔT

Where,
Cp = Specific heat capacity at constant pressure
Cv = Specific heat capacity at constant volume

Calculation:
To find the specific heat capacity at constant volume (Cv), we can use the relationship between Cp and Cv:
Cp - Cv = R
Where R is the gas constant.

For an ideal gas, R = 8.314 J/mol K

Cv = Cp - R
= 20.79 J/mol K

Now we can use the formula for qV:
qV = nCvΔT
= 4 mol * 20.79 J/mol K * 5°C
= 415.8 J
= 0.1 kcal
= 100 cal

Answer:
The amount of heat required to raise the temperature of the same gas through the same temperature range at constant volume is 100 cal.
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140 cal of heat is required to raise the temperature of 4 mole of an ideal gas at constant pressure from 40 to 45degree Celsius . what is the amount of heat required to raise temperature of same gas through same temperature of constant volume? Ans: 100 cal explain?
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