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C4H10O represents methoxypropane (CH3OC3H7) and ethoxyethane (C2H5O C2H5)
  • a)
    Stereoisomerism
  • b)
    Functional group isomerism
  • c)
    Metamerism
  • d)
    isomerism
Correct answer is option 'C'. Can you explain this answer?
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C4H10Orepresents methoxypropane(CH3OC3H7)and ethoxyethane(C2H5OC2H5)a)...
rearrangement of carbon atoms around the functional group is known as metamerism.
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C4H10Orepresents methoxypropane(CH3OC3H7)and ethoxyethane(C2H5OC2H5)a)...
Metamerism is a type of isomerism in organic chemistry where compounds have the same molecular formula but differ in the nature and arrangement of the alkyl groups attached to the functional group. In the given example, the compounds methoxypropane (CH3OC3H7) and ethoxyethane (C2H5OC2H5) exhibit metamerism.

Explanation:
Methoxypropane (CH3OC3H7) and ethoxyethane (C2H5OC2H5) have the same molecular formula, C4H10O, but differ in the nature and arrangement of the alkyl groups attached to the oxygen atom.

In methoxypropane, the alkyl group attached to the oxygen atom is propyl (C3H7), whereas in ethoxyethane, the alkyl group attached to the oxygen atom is ethyl (C2H5).

This difference in alkyl groups leads to a difference in the physical and chemical properties of the compounds. For example, methoxypropane has a higher boiling point compared to ethoxyethane.

Hence, methoxypropane and ethoxyethane exhibit metamerism because they have the same molecular formula (C4H10O) but differ in the nature and arrangement of the alkyl groups attached to the functional group (oxygen atom).

In summary, metamerism is a type of isomerism where compounds have the same molecular formula but differ in the nature and arrangement of the alkyl groups attached to the functional group. Methoxypropane and ethoxyethane are examples of compounds that exhibit metamerism.
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C4H10Orepresents methoxypropane(CH3OC3H7)and ethoxyethane(C2H5OC2H5)a)Stereoisomerismb)Functional group isomerismc)Metamerismd)isomerismCorrect answer is option 'C'. Can you explain this answer?
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