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A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.
 
Q. If Q and R are treated separately with HBr, the correct statement concerning addition product is
  • a)
    A single bromoalkane is formed in both cases
  • b)
    A pair of diastereomers are formed in both cases
  • c)
    A pair of enantiomers in equal amounts are formed in both ca
  • d)
    None of the above
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A mixture of hydrocarbons contain three compounds P, Q and R. Q and R ...
Mixture of hydrocarbons:
- Contains three compounds: P, Q, and R
- Q and R are stereoisomers

Treatment with cold, concentrated H2SO4:
- Q and R get absorbed
- P remains unreacted and forms a separate layer at the surface

Separation of P:
- Acid solution is heated
- Q and R, predominantly Q, are recovered

Vaporization and passing over heated Ni with H2 gas:
- A single alkane of six carbon is obtained

Treatment of Q with Br2/CCI4 in the presence of FeBr3:
- Meso dibromide is formed

Treatment of Q and R separately with HBr:
- The correct statement concerning the addition product is that a pair of enantiomers in equal amounts are formed in both cases (option C)

Explanation:

The reaction of Q and R with HBr results in the addition of a bromine atom to the hydrocarbon. Since Q and R are stereoisomers, they have the same molecular formula but differ in their spatial arrangement. When treated with HBr, both Q and R will form pairs of enantiomers, which are mirror images of each other.

Enantiomers have the same connectivity of atoms but differ in their spatial arrangement. They are non-superimposable mirror images of each other. When a chiral molecule reacts with an achiral reagent like HBr, it can form a pair of enantiomers.

In this case, Q and R are stereoisomers, which means they have the same molecular formula and connectivity of atoms but differ in their spatial arrangement. Therefore, when treated separately with HBr, both Q and R will form pairs of enantiomers. Since the question states that Q and R are stereoisomers, the correct statement is that a pair of enantiomers in equal amounts are formed in both cases (option C).
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A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.Q.If Q and R are treated separately with HBr, thecorrect statement concerning addition product isa)A single bromoalkane is formed in both casesb)A pair of diastereomers are formed in both casesc)A pair of enantiomers in equal amounts are formed in both cad)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
Question Description
A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.Q.If Q and R are treated separately with HBr, thecorrect statement concerning addition product isa)A single bromoalkane is formed in both casesb)A pair of diastereomers are formed in both casesc)A pair of enantiomers in equal amounts are formed in both cad)None of the aboveCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.Q.If Q and R are treated separately with HBr, thecorrect statement concerning addition product isa)A single bromoalkane is formed in both casesb)A pair of diastereomers are formed in both casesc)A pair of enantiomers in equal amounts are formed in both cad)None of the aboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.Q.If Q and R are treated separately with HBr, thecorrect statement concerning addition product isa)A single bromoalkane is formed in both casesb)A pair of diastereomers are formed in both casesc)A pair of enantiomers in equal amounts are formed in both cad)None of the aboveCorrect answer is option 'C'. Can you explain this answer?.
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