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Passage I
An unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.
Q.
What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?
What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?
- a)A pure enantiomer of Y gives racemic mixture
- b)A pure enantiomer of Y gives a pair of achiral isomers
- c)A pure enantiomer of Y gives a pair of optically active diastereomers
- d)Y is achiral.it gives racemic mixture
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Passage IAn unknown compound X (C5HgBr) does not decolourise purple co...
A diastereomer is a stereoisomer with two or more stereocenters and the isomers are not mirror images of each other.
If a molecule has more than one stereocenter and every single stereocenter isn’t in the opposite direction then they are diastereomers. diastereomers will always have non-identical (but non-opposite) R,S designations.
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Passage IAn unknown compound X (C5HgBr) does not decolourise purple co...
Reaction of compound Y with cold, dilute alkaline KMnO4 solution:
- When Y reacts with cold, dilute alkaline KMnO4 solution, it does not decolorize the solution. This indicates that Y is not easily oxidizable and does not contain any unsaturated bonds that can be oxidized.
- The lack of reaction with KMnO4 suggests that Y does not contain any carbon-carbon double or triple bonds.
Structure of compound Y:
- The only structural isomer of Y is methyl cyclobutane, which is formed by the catalytic hydrogenation of Y.
- This indicates that Y contains a cyclobutane ring and no other functional groups.
Formation of compound Z:
- Ozonolysis of Y gives compound Z, which exists as a pair of enantiomers.
- This suggests that Y contains a double bond that is susceptible to ozonolysis, resulting in the formation of two enantiomeric products.
Interpretation:
- The lack of reactivity of Y with cold, dilute alkaline KMnO4 solution and its ability to form a pair of enantiomers upon ozonolysis indicates that Y is an optically active compound.
- Since Y is optically active, it cannot be achiral.
- The formation of optically active diastereomers upon ozonolysis suggests that Y is a chiral compound.
- Therefore, the correct answer is option 'C': A pure enantiomer of Y gives a pair of optically active diastereomers.
- When Y reacts with cold, dilute alkaline KMnO4 solution, it does not decolorize the solution. This indicates that Y is not easily oxidizable and does not contain any unsaturated bonds that can be oxidized.
- The lack of reaction with KMnO4 suggests that Y does not contain any carbon-carbon double or triple bonds.
Structure of compound Y:
- The only structural isomer of Y is methyl cyclobutane, which is formed by the catalytic hydrogenation of Y.
- This indicates that Y contains a cyclobutane ring and no other functional groups.
Formation of compound Z:
- Ozonolysis of Y gives compound Z, which exists as a pair of enantiomers.
- This suggests that Y contains a double bond that is susceptible to ozonolysis, resulting in the formation of two enantiomeric products.
Interpretation:
- The lack of reactivity of Y with cold, dilute alkaline KMnO4 solution and its ability to form a pair of enantiomers upon ozonolysis indicates that Y is an optically active compound.
- Since Y is optically active, it cannot be achiral.
- The formation of optically active diastereomers upon ozonolysis suggests that Y is a chiral compound.
- Therefore, the correct answer is option 'C': A pure enantiomer of Y gives a pair of optically active diastereomers.
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Passage IAn unknown compound X (C5HgBr) does not decolourise purple co...
C is correct
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Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer?
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Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer?.
Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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Here you can find the meaning of Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Passage IAn unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.Q.What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?a)A pure enantiomer of Y gives racemic mixtureb)A pure enantiomer of Y gives a pair of achiral isomersc)A pure enantiomer of Y gives a pair of optically active diastereomersd)Y is achiral.it gives racemic mixtureCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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