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If all stereoisomers of 2-pentene are treated with cold, dilute and alkaline KMn04 solution, how many different diols would be expected?
    Correct answer is '4'. Can you explain this answer?
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    Explanation:

    Number of stereoisomers of 2-pentene:
    - 2-pentene has two stereocenters, leading to a total of 4 stereoisomers:
    1. (Z,Z)-2-pentene
    2. (Z,E)-2-pentene
    3. (E,Z)-2-pentene
    4. (E,E)-2-pentene

    Reaction with cold, dilute, and alkaline KMnO4:
    - The reaction of 2-pentene with cold, dilute, and alkaline KMnO4 leads to the formation of diols.
    - The diols formed will depend on the orientation of the double bonds in the stereoisomers.

    Number of different diols expected:
    - For each stereoisomer of 2-pentene, a different diol is expected to be formed due to the different orientations of the double bonds.
    - Therefore, since there are 4 stereoisomers of 2-pentene, we would expect 4 different diols to be formed when each stereoisomer is treated with cold, dilute, and alkaline KMnO4 solution.

    Conclusion:
    - In summary, when all stereoisomers of 2-pentene are treated with cold, dilute, and alkaline KMnO4 solution, 4 different diols would be expected to be formed due to the different orientations of the double bonds in each stereoisomer.
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