Chemistry Exam  >  Chemistry Questions  >  The electron affinity of chlorine is +37 eV. ... Start Learning for Free
The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl ion in the gaseous state. (1eV = 96.45 kJ/mol)
(rounded up to first decimal place)
    Correct answer is between '356.5,357.5'. Can you explain this answer?
    Most Upvoted Answer
    The electron affinity of chlorine is +37 eV. How much energy in kJ is ...
    Electron affinity for 1 mole of chlorine is 37ev =3568.65 kj/mole
    E.A. for 3.55/35.5 mole of Cl = 3568.65×3.55/35.5 = 356.86 kj
    Free Test
    Community Answer
    The electron affinity of chlorine is +37 eV. How much energy in kJ is ...
    To find the energy released when 3.55 g of chlorine is converted completely into Cl-, we need to calculate the moles of chlorine and then use the molar electron affinity to find the energy released.

    1. Calculate the moles of chlorine:
    Molar mass of Cl = 35.45 g/mol
    moles = mass / molar mass
    moles = 3.55 g / 35.45 g/mol
    moles = 0.1 mol

    2. Use the molar electron affinity to find the energy released:
    Electron affinity = 37 eV
    1 eV = 96.485 kJ/mol
    Energy released = electron affinity * moles * 96.485 kJ/mol
    Energy released = 37 eV * 0.1 mol * 96.485 kJ/mol
    Energy released = 354.84 kJ

    Therefore, when 3.55 g of chlorine is converted completely into Cl-, 354.84 kJ of energy is released.
    Explore Courses for Chemistry exam
    The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer?
    Question Description
    The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer?.
    Solutions for The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
    Here you can find the meaning of The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer?, a detailed solution for The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? has been provided alongside types of The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The electron affinity of chlorine is +37 eV. How much energy in kJ is released when 3.55 g of chlorine is converted completely into Cl– ion in the gaseous state. (1eV = 96.45 kJ/mol)(rounded up to first decimal place)Correct answer is between '356.5,357.5'. Can you explain this answer? tests, examples and also practice Chemistry tests.
    Explore Courses for Chemistry exam
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev