Empirical Formula Calculation:
The molar mass of the compound is given as 58 g/mol. The empirical formula of the compound is C2H5.
To find the empirical formula, we need to determine the simplest whole number ratio between the atoms present in the compound.

Calculating the Molar Mass of C2H5:
Molar mass of C (Carbon) = 12 g/mol
Molar mass of H (Hydrogen) = 1 g/mol
Total molar mass of C2H5 = (2*12) + (5*1) = 24 + 5 = 29 g/mol

Finding the Empirical Formula:
Dividing the molar mass of the compound by the molar mass of the empirical formula:
58 g/mol (given molar mass) / 29 g/mol (molar mass of C2H5) = 2
Thus, the empirical formula of the compound is C2H5.

Structural Isomerism:
Structural isomerism occurs when compounds have the same molecular formula but different structural arrangements of atoms. In the case of C2H5, which is the empirical formula for the compound, there are two possible structural isomers based on the arrangement of carbon and hydrogen atoms.
1. Ethane (C2H6):
- This isomer consists of two carbon atoms bonded to each other with five hydrogen atoms attached to the carbons.
2. Ethyl alcohol (C2H5OH):
- This isomer has two carbon atoms bonded together with five hydrogen atoms and one oxygen atom attached to one of the carbons.
Therefore, there are two possible structural isomers for the compound with the empirical formula C2H5.