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Two parts A and B of a machine is manufactured by a firm. Out of 100 A’s 12 are likely to be defective and Out of 100 B’s 8 are likely to be defective. The probability that a machine manufactured by the firm is free from any defect is:​
  • a)
    619/625
  • b)
    119/625
  • c)
    6/625
  • d)
    506/625
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two parts A and B of a machine is manufactured by a firm. Out of 100 A...
 probability of getting good machine part from A = 88/100
probability of getting good machine part from B = 92/100
P(correction) = (88/100)(92/100)
= 506/625
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Most Upvoted Answer
Two parts A and B of a machine is manufactured by a firm. Out of 100 A...
It's just case of combined probability as the probability of getting good machine part form A= 88/100 and from B =92/100 and by combining each ie 88/100*92/100=8096/10000 or 0.8096 or by simplifying we get 506/625...
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Community Answer
Two parts A and B of a machine is manufactured by a firm. Out of 100 A...
To solve this problem, we can use the concept of conditional probability. We need to find the probability that both part A and part B are free from defects.

Let's denote the event "part A is free from defects" as A, and the event "part B is free from defects" as B.

Given information:
P(A being defective) = 12/100 = 3/25
P(B being defective) = 8/100 = 2/25

To find the probability that both parts are free from defects, we can use the formula for conditional probability:
P(A and B) = P(A) * P(B|A)

where P(B|A) is the probability of B given that A has occurred.

From the given information, we know that out of 100 parts A, 12 are likely to be defective. So, the probability that part A is free from defects is:
P(A) = 1 - P(A being defective) = 1 - 3/25 = 22/25

Now, we need to find the probability that part B is free from defects given that part A is free from defects. Since the two events are independent (one part being defective does not affect the other part), the probability of part B being free from defects is the same regardless of whether part A is defective or not. So, we can directly use the given information:
P(B|A) = 1 - P(B being defective) = 1 - 2/25 = 23/25

Calculating the probability that both parts are free from defects:
P(A and B) = P(A) * P(B|A) = (22/25) * (23/25) = 506/625

Therefore, the probability that a machine manufactured by the firm is free from any defect is 506/625.

Hence, the correct answer is option D) 506/625.
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Two parts A and B of a machine is manufactured by a firm. Out of 100 A’s 12 are likely to be defective and Out of 100 B’s 8 are likely to be defective. The probability that a machine manufactured by the firm is free from any defect is:​a)619/625b)119/625c)6/625d)506/625Correct answer is option 'D'. Can you explain this answer?
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Two parts A and B of a machine is manufactured by a firm. Out of 100 A’s 12 are likely to be defective and Out of 100 B’s 8 are likely to be defective. The probability that a machine manufactured by the firm is free from any defect is:​a)619/625b)119/625c)6/625d)506/625Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two parts A and B of a machine is manufactured by a firm. Out of 100 A’s 12 are likely to be defective and Out of 100 B’s 8 are likely to be defective. The probability that a machine manufactured by the firm is free from any defect is:​a)619/625b)119/625c)6/625d)506/625Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two parts A and B of a machine is manufactured by a firm. Out of 100 A’s 12 are likely to be defective and Out of 100 B’s 8 are likely to be defective. The probability that a machine manufactured by the firm is free from any defect is:​a)619/625b)119/625c)6/625d)506/625Correct answer is option 'D'. Can you explain this answer?.
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