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Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz?
Most Upvoted Answer
Speed of sound in air is 333 m/s.The fundamental frequency of an open ...
Fundamental frequency = 333
v/2l = 333
333/2l = 333
1/2l = 1
l = 1/2 = 0.5
Not sure about the solution
v/2l = 333
333/2l = 333
1/2l = 1
l = 1/2 = 0.5
Not sure about the solution
Community Answer
Speed of sound in air is 333 m/s.The fundamental frequency of an open ...
Speed of Sound in Air:
The speed of sound in air is given as 333 m/s.
Fundamental Frequency of an Open Pipe:
The fundamental frequency of an open pipe is given as 333 Hz.
Calculation of Pipe Length for 2nd Overtone:
To find the length of the pipe required to produce the 2nd overtone, we need to understand the concept of harmonics in pipes.
- Harmonics in Pipes:
When a pipe is open at both ends, it can produce harmonics or overtones. The fundamental frequency is the first harmonic, the first overtone is the second harmonic, the second overtone is the third harmonic, and so on.
- Relationship between Frequency and Length:
The fundamental frequency of an open pipe is determined by its length. The formula for the fundamental frequency of an open pipe is given as:
f1 = v / (2L)
where f1 is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.
- Calculating the 2nd Overtone:
The 2nd overtone is the third harmonic, so its frequency can be calculated as:
f3 = 3 * f1
Substituting the given values, we have:
f3 = 3 * 333 Hz = 999 Hz
- Finding the Length of the Pipe:
Now, we can rearrange the formula for the fundamental frequency to find the length of the pipe required for the 2nd overtone:
L = v / (2 * f3)
Substituting the given values, we have:
L = 333 m/s / (2 * 999 Hz) = 333 m/s / 1998 s^-1 = 0.1665 m = 0.17 m (rounded to two decimal places)
Therefore, the length of the pipe required to produce the 2nd overtone is approximately 0.17 meters or 17 cm.
However, the given answer is 0.5 m, which does not match the calculated value. It is possible that there was an error in the answer provided.
The speed of sound in air is given as 333 m/s.
Fundamental Frequency of an Open Pipe:
The fundamental frequency of an open pipe is given as 333 Hz.
Calculation of Pipe Length for 2nd Overtone:
To find the length of the pipe required to produce the 2nd overtone, we need to understand the concept of harmonics in pipes.
- Harmonics in Pipes:
When a pipe is open at both ends, it can produce harmonics or overtones. The fundamental frequency is the first harmonic, the first overtone is the second harmonic, the second overtone is the third harmonic, and so on.
- Relationship between Frequency and Length:
The fundamental frequency of an open pipe is determined by its length. The formula for the fundamental frequency of an open pipe is given as:
f1 = v / (2L)
where f1 is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.
- Calculating the 2nd Overtone:
The 2nd overtone is the third harmonic, so its frequency can be calculated as:
f3 = 3 * f1
Substituting the given values, we have:
f3 = 3 * 333 Hz = 999 Hz
- Finding the Length of the Pipe:
Now, we can rearrange the formula for the fundamental frequency to find the length of the pipe required for the 2nd overtone:
L = v / (2 * f3)
Substituting the given values, we have:
L = 333 m/s / (2 * 999 Hz) = 333 m/s / 1998 s^-1 = 0.1665 m = 0.17 m (rounded to two decimal places)
Therefore, the length of the pipe required to produce the 2nd overtone is approximately 0.17 meters or 17 cm.
However, the given answer is 0.5 m, which does not match the calculated value. It is possible that there was an error in the answer provided.
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Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz?
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Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz?.
Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Speed of sound in air is 333 m/s.The fundamental frequency of an open pipe 333HZ .The 2nd overtone of the open organ pipe can be produced with a pipe of length. Ans is 0.5m? can have explanation of solun plz?.
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