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Circular arc on a part profile is being machined on a vertical CNC milling machine. CNC part program using metric units with absolute dimensions is listed below: -----------------------------
N60 G01 X 30 Y 55 Z – 5 F 50
N70 G02 X 50 Y 35 R 20
N80 G01 Z 5
--------------------------------
The coordinates of the centre of the circular arc are :
- a)(30, 55)
- b)(50, 55)
- c)(50, 35)
- d)(30, 35)
Correct answer is option 'D'. Can you explain this answer?
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Circular arc on a part profile is being machined on a vertical CNC mil...
Centre of circular arc is (30, 35)
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Circular arc on a part profile is being machined on a vertical CNC mil...
Centre of circular arc is (30, 35)
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Circular arc on a part profile is being machined on a vertical CNC mil...
Explanation:
Given CNC Part Program:
N60 G01 X 30 Y 55 Z 5 F 50
N70 G02 X 50 Y 35 R 20
N80 G01 Z 5
Finding the Center of the Circular Arc:
- The G02 command in line N70 indicates a clockwise circular interpolation.
- The X and Y coordinates specify the end point of the arc, which is (50, 35).
- The R value in the G02 command gives the radius of the circle, which is 20 units.
- To find the center of the circle, we need to move back along the perpendicular bisector of the line joining the start and end points by the radius distance.
Calculations:
- Midpoint between the start point (X=30, Y=55) and end point (X=50, Y=35) is ((30+50)/2, (55+35)/2) = (40, 45).
- Slope of the line joining the start and end points is (55-35)/(30-50) = 20/-20 = -1.
- Slope of the perpendicular bisector is the negative reciprocal of -1, which is 1.
- Equation of the perpendicular bisector passing through the midpoint (40, 45) is (Y-45) = 1(X-40).
- Moving back by the radius distance of 20 units gives the center as (40-20, 45-20) = (20, 25).
Therefore, the coordinates of the center of the circular arc being machined on the part profile are (30, 35), which is option 'D'.
Given CNC Part Program:
N60 G01 X 30 Y 55 Z 5 F 50
N70 G02 X 50 Y 35 R 20
N80 G01 Z 5
Finding the Center of the Circular Arc:
- The G02 command in line N70 indicates a clockwise circular interpolation.
- The X and Y coordinates specify the end point of the arc, which is (50, 35).
- The R value in the G02 command gives the radius of the circle, which is 20 units.
- To find the center of the circle, we need to move back along the perpendicular bisector of the line joining the start and end points by the radius distance.
Calculations:
- Midpoint between the start point (X=30, Y=55) and end point (X=50, Y=35) is ((30+50)/2, (55+35)/2) = (40, 45).
- Slope of the line joining the start and end points is (55-35)/(30-50) = 20/-20 = -1.
- Slope of the perpendicular bisector is the negative reciprocal of -1, which is 1.
- Equation of the perpendicular bisector passing through the midpoint (40, 45) is (Y-45) = 1(X-40).
- Moving back by the radius distance of 20 units gives the center as (40-20, 45-20) = (20, 25).
Therefore, the coordinates of the center of the circular arc being machined on the part profile are (30, 35), which is option 'D'.
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Circular arc on a part profile is being machined on a vertical CNC milling machine. CNC part program using metric units with absolute dimensions is listed below: -----------------------------N60 G01 X 30 Y 55 Z – 5 F 50N70 G02 X 50 Y 35 R 20N80 G01 Z 5--------------------------------The coordinates of the centre of the circular arc are :a)(30, 55)b)(50, 55)c)(50, 35)d)(30, 35)Correct answer is option 'D'. Can you explain this answer?
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Circular arc on a part profile is being machined on a vertical CNC milling machine. CNC part program using metric units with absolute dimensions is listed below: -----------------------------N60 G01 X 30 Y 55 Z – 5 F 50N70 G02 X 50 Y 35 R 20N80 G01 Z 5--------------------------------The coordinates of the centre of the circular arc are :a)(30, 55)b)(50, 55)c)(50, 35)d)(30, 35)Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Circular arc on a part profile is being machined on a vertical CNC milling machine. CNC part program using metric units with absolute dimensions is listed below: -----------------------------N60 G01 X 30 Y 55 Z – 5 F 50N70 G02 X 50 Y 35 R 20N80 G01 Z 5--------------------------------The coordinates of the centre of the circular arc are :a)(30, 55)b)(50, 55)c)(50, 35)d)(30, 35)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Circular arc on a part profile is being machined on a vertical CNC milling machine. CNC part program using metric units with absolute dimensions is listed below: -----------------------------N60 G01 X 30 Y 55 Z – 5 F 50N70 G02 X 50 Y 35 R 20N80 G01 Z 5--------------------------------The coordinates of the centre of the circular arc are :a)(30, 55)b)(50, 55)c)(50, 35)d)(30, 35)Correct answer is option 'D'. Can you explain this answer?.
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