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 If the pu impedance of a single phase transformer is 0.01+j0.05, then its regulation at p.f. of 0.8 lagging will be
  • a)
    3.8%
  • b)
    2.2%
  • c)
    -3.8%
  • d)
    -2.2%
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If the pu impedance of a single phase transformer is 0.01+j0.05, then ...
V.R. = (r(pu)*cosθ+x(pu)*sinθ)*100 % = (0.01*0.8 + 0.05*0.6)*100 = 3.8%
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Most Upvoted Answer
If the pu impedance of a single phase transformer is 0.01+j0.05, then ...
Explanation:

The regulation of a transformer is a measure of how well it maintains its rated voltage when the load changes. It is defined as the percentage change in voltage from no-load to full-load conditions.

Given data:
Pu impedance of the transformer = 0.01 j0.05
Power factor (p.f.) = 0.8 lagging

To find the regulation, we need to calculate the voltage drop in the transformer at full load and then calculate the percentage change from no-load to full-load conditions.

Step 1: Calculate the impedance of the transformer:
The given impedance of the transformer is in per-unit (pu) values. To calculate the actual impedance, we need to multiply it by the base impedance.

Let's assume the base impedance of the transformer as Zbase. We can calculate Zbase using the rated voltage and power of the transformer.

Step 2: Calculate the voltage drop at full load:
The voltage drop in the transformer can be calculated using the formula:
Voltage drop = Iload * Z

Where,
Iload = Full load current
Z = Impedance of the transformer

Step 3: Calculate the regulation:
The regulation is given by the formula:
Regulation = ((Vno-load - Vfull-load) / Vno-load) * 100

Where,
Vno-load = Voltage at no-load
Vfull-load = Voltage at full-load

Step 4: Substitute the given values and calculate the regulation:
In this case, the power factor is given as 0.8 lagging. This means that the load is capacitive.

Step 4a: Calculate the load current:
The load current can be calculated using the formula:
Iload = Pload / (Vload * p.f.)

Where,
Pload = Load power
Vload = Load voltage
p.f. = Power factor

Step 4b: Calculate the voltage at full load:
The voltage at full load can be calculated using the formula:
Vfull-load = Vno-load - Voltage drop

Step 4c: Calculate the regulation:
Use the formula for regulation mentioned in Step 3.

Final Answer:
The correct answer is option 'A', i.e., 3.8%.
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If the pu impedance of a single phase transformer is 0.01+j0.05, then its regulation at p.f. of 0.8 lagging will bea)3.8%b)2.2%c)-3.8%d)-2.2%Correct answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about If the pu impedance of a single phase transformer is 0.01+j0.05, then its regulation at p.f. of 0.8 lagging will bea)3.8%b)2.2%c)-3.8%d)-2.2%Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the pu impedance of a single phase transformer is 0.01+j0.05, then its regulation at p.f. of 0.8 lagging will bea)3.8%b)2.2%c)-3.8%d)-2.2%Correct answer is option 'A'. Can you explain this answer?.
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