Perimeter of the Rhombus:
The perimeter of a rhombus is the sum of the lengths of all its sides. Let's assume the lengths of the sides of the rhombus as a, b, c, and d.

Since a rhombus has four equal sides, we can write:
a + b + c + d = 100m

Length of the Diagonal:
A rhombus has two diagonals that intersect at a right angle, bisecting each other. Let's assume one diagonal as p and the other diagonal as q.

According to the given information, the length of one diagonal (p) is 30m.

Using the Properties of a Rhombus:
In a rhombus, the diagonals bisect each other and are perpendicular. Therefore, we can divide the rhombus into four right triangles.

Using the Pythagorean theorem, we can find the lengths of the sides of each right triangle:
p^2 = (a/2)^2 + (b/2)^2
30^2 = (a/2)^2 + (b/2)^2
900 = a^2/4 + b^2/4
3600 = a^2 + b^2

Similarly, for the other right triangles formed by the diagonals, we have:
3600 = c^2 + d^2

Solving the Equations:
We have the following equations:
a + b + c + d = 100
a^2 + b^2 = 3600
c^2 + d^2 = 3600

Using the first equation, we can rewrite it as:
a + b = 100 - (c + d)

Substituting this value in the second equation:
(100 - (c + d))^2 + b^2 = 3600

Expanding and simplifying:
10000 - 200(c + d) + (c + d)^2 + b^2 = 3600
10000 - 200(c + d) + c^2 + 2cd + d^2 + b^2 = 3600

Rearranging the equation:
c^2 + d^2 + b^2 - 200(c + d) + 6400 = 0

Using the Diagonal Length:
We also know that the length of one diagonal is 30m. Using this information, we can find the relationship between the sides and the diagonals.

In a rhombus, the diagonals bisect each other and are perpendicular. Therefore, we can write the following equation:
(p/2)^2 + (q/2)^2 = a^2/4 + b^2/4

Substituting the values, we have:
(30/2)^2 + q^2/4 = a^2/4 + b^2/4
225 + q^2/4 = a^2/4 + b^2/4
900 + q^2 = a^2 + b^2
900 + q^2 = 3600

Solving for q:
q^2 = 2700
q = √2700
q ≈ 51.96m

Calculating the Area:
We know

4*side=100
side=25
one diagonal=30 cm
d/2 sq+ 15 sq=25sq
d/2 sq= 625-225=400
d/2=20
d= 40
area= 40*30/2=600
600cm sq