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10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is?
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10 ml of hcl solution give 0.1435 gm of agcl when treated with excess ...
Calculation of Normality of HCl Solution
Explanation
The given problem states that 10 ml of HCl solution gives 0.1435 gm of AgCl when treated with excess of AgNO3. This indicates that the HCl solution is reacting with AgNO3 to form AgCl. The balanced chemical equation for this reaction is:
HCl + AgNO3 → AgCl + HNO3
From the given data, the mass of AgCl formed is 0.1435 g. Using the molar mass of AgCl, we can calculate the number of moles of AgCl formed. Since 1 mole of HCl reacts with 1 mole of AgCl, the number of moles of HCl used can be calculated from the number of moles of AgCl formed.
The volume of HCl used is given as 10 ml. To calculate the Normality of HCl solution, we need to divide the number of moles of HCl used by the volume of HCl in liters. The Normality of HCl solution is found to be 0.1 N.
- Calculate the number of moles of AgCl:
- Mass of AgCl = 0.1435 g
- Molar mass of AgCl = 143.32 g/mol
- Number of moles of AgCl = 0.1435 g / 143.32 g/mol = 0.001
- Calculate the number of moles of HCl used:
- 1 mole of HCl reacts with 1 mole of AgCl
- Therefore, the number of moles of HCl used = 0.001
- Calculate the volume of HCl used:
- Volume of HCl used = 10 ml = 0.01 L
- Calculate the Normality of HCl Solution:
- Normality = Number of moles of HCl / Volume of HCl in L
- Normality = 0.001 / 0.01 = 0.1 N
Explanation
The given problem states that 10 ml of HCl solution gives 0.1435 gm of AgCl when treated with excess of AgNO3. This indicates that the HCl solution is reacting with AgNO3 to form AgCl. The balanced chemical equation for this reaction is:
HCl + AgNO3 → AgCl + HNO3
From the given data, the mass of AgCl formed is 0.1435 g. Using the molar mass of AgCl, we can calculate the number of moles of AgCl formed. Since 1 mole of HCl reacts with 1 mole of AgCl, the number of moles of HCl used can be calculated from the number of moles of AgCl formed.
The volume of HCl used is given as 10 ml. To calculate the Normality of HCl solution, we need to divide the number of moles of HCl used by the volume of HCl in liters. The Normality of HCl solution is found to be 0.1 N.
Community Answer
10 ml of hcl solution give 0.1435 gm of agcl when treated with excess ...
HCl + AgNO3 …............>AgCl+ HNO3
10ml …...excess .... ….............0
0ml …..excess.. …..................0.1435g
...................................................=(0.1435/143.5) mol
=0.001mol AgCl made by 10 ml of HCl
From reaction it is clear that,
1 mole of AgCl would be obtained by1 mole HCl
So number of moles of HCl in 10ml would be=0.001
SO number of equivalents of HCl in 10ml = 0.001*1 …..(as basicity of HCl =1)
Hence normality of HCl=(number of equivalents of HCl/volume of HCl in ml)*1000
normality= (0.001/10)*1000=0.1N
10ml …...excess .... ….............0
0ml …..excess.. …..................0.1435g
...................................................=(0.1435/143.5) mol
=0.001mol AgCl made by 10 ml of HCl
From reaction it is clear that,
1 mole of AgCl would be obtained by1 mole HCl
So number of moles of HCl in 10ml would be=0.001
SO number of equivalents of HCl in 10ml = 0.001*1 …..(as basicity of HCl =1)
Hence normality of HCl=(number of equivalents of HCl/volume of HCl in ml)*1000
normality= (0.001/10)*1000=0.1N
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10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is?
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10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is?.
10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10 ml of hcl solution give 0.1435 gm of agcl when treated with excess of agno3 the noramality of hcl solution is?.
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