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We did not find results for: you are given with 500 ml of 2 M HCl and 500 mL of 5M HCl . what will be the max vol of 3M HCl that you can make from these two sol.
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We did not find results for: you are given with 500 ml of 2 M HCl and ...
Given Information:
- Volume of 2 M HCl = 500 mL
- Volume of 5 M HCl = 500 mL

To find:
- Maximum volume of 3 M HCl that can be made from these two solutions

Solution:
Step 1: Calculate the moles of HCl in each solution.
Moles = Molarity x Volume (in liters)

Moles of HCl in 2 M solution:
Moles = 2 M x 0.5 L = 1 mol

Moles of HCl in 5 M solution:
Moles = 5 M x 0.5 L = 2.5 mol

Step 2: Calculate the total moles of HCl.
Total moles = Moles from 2 M solution + Moles from 5 M solution
Total moles = 1 mol + 2.5 mol = 3.5 mol

Step 3: Calculate the volume of 3 M HCl that can be made.
Molarity = Moles / Volume (in liters)

Volume of 3 M HCl = Moles / Molarity
Volume of 3 M HCl = 3.5 mol / 3 M = 1.17 L = 1170 mL

Step 4: Verify the maximum volume.
Since the volume of the final solution is limited by the volume of the starting solutions, the maximum volume of 3 M HCl that can be made is equal to the minimum volume of the starting solutions, which is 500 mL.

Conclusion:
The maximum volume of 3 M HCl that can be made from the given solutions is 500 mL.
Community Answer
We did not find results for: you are given with 500 ml of 2 M HCl and ...
By using given equation we can find max bol
given M1=2M,M2=5M
V1=500ml,V2=500ml
M=3M,V=?
MV=M2V2-M1V1
M=500*5-500*2/3
M=500ml
max vol is 500ml
if I am wrong then correct me
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We did not find results for: you are given with 500 ml of 2 M HCl and 500 mL of 5M HCl . what will be the max vol of 3M HCl that you can make from these two sol.
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