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Which of the following statements is correct?
Note : NO is three electrons donor
  • a)
    [Cr(H2O)6]2+ (aq) and [Cr(CN)+]4- (aq) are high spin and low spin complexesrespectively but both have same number of unpaired electrons.
  • b)
    [V(NH3)6]3+ is inner orbital complex and paramagnetic with two unpaired electrons.
  • c)
    [Co(CN6)]4- is outer orbital complex and paramagnetic with three unpaired electrons.
  • d)
    [Mn(NO)3(CO)] is square planar and diamagnetic.
Correct answer is option 'B'. Can you explain this answer?
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Which of the following statements is correct?Note : NO is three electr...
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Which of the following statements is correct?Note : NO is three electr...
Explanation:

Paramagnetism and diamagnetism are the two fundamental properties displayed by the coordination compounds, depending on the presence or absence of unpaired electrons.

a) [Cr(H2O)6]2+ (aq) and [Cr(CN)6]4- (aq) both are high spin and low spin complexes, respectively, but both have the same number of unpaired electrons.

- [Cr(H2O)6]2+ (aq) is a high spin complex with four unpaired electrons.
- [Cr(CN)6]4- (aq) is a low spin complex with no unpaired electrons.

b) [V(NH3)6]3+ is an inner orbital complex and paramagnetic with two unpaired electrons.

- [V(NH3)6]3+ has a d3 configuration, and it is an inner orbital complex because the electrons are first filled in the inner d orbitals and then in the outer d orbitals.
- The two unpaired electrons are present in the outer d orbitals, which gives rise to paramagnetism.

c) [Co(CN)6]4- is an outer orbital complex and paramagnetic with three unpaired electrons.

- [Co(CN)6]4- has a d6 configuration, and it is an outer orbital complex because the electrons are first filled in the outer d orbitals and then in the inner d orbitals.
- The three unpaired electrons are present in the outer d orbitals, which gives rise to paramagnetism.

d) [Mn(NO)3(CO)] is square planar and diamagnetic.

- [Mn(NO)3(CO)] has a d6 configuration, and it is square planar because the ligands are arranged in a plane around the central metal atom.
- The six electrons are paired up in the d orbitals, which gives rise to diamagnetism.

Therefore, option B is the correct answer.
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Which of the following statements is correct?Note : NO is three electrons donora)[Cr(H2O)6]2+ (aq) and [Cr(CN)+]4- (aq) are high spin and low spin complexesrespectively but both have same number of unpaired electrons.b)[V(NH3)6]3+ is inner orbital complex and paramagnetic with two unpaired electrons.c)[Co(CN6)]4- is outer orbital complex and paramagnetic with three unpaired electrons.d)[Mn(NO)3(CO)] is square planar and diamagnetic.Correct answer is option 'B'. Can you explain this answer?
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Which of the following statements is correct?Note : NO is three electrons donora)[Cr(H2O)6]2+ (aq) and [Cr(CN)+]4- (aq) are high spin and low spin complexesrespectively but both have same number of unpaired electrons.b)[V(NH3)6]3+ is inner orbital complex and paramagnetic with two unpaired electrons.c)[Co(CN6)]4- is outer orbital complex and paramagnetic with three unpaired electrons.d)[Mn(NO)3(CO)] is square planar and diamagnetic.Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following statements is correct?Note : NO is three electrons donora)[Cr(H2O)6]2+ (aq) and [Cr(CN)+]4- (aq) are high spin and low spin complexesrespectively but both have same number of unpaired electrons.b)[V(NH3)6]3+ is inner orbital complex and paramagnetic with two unpaired electrons.c)[Co(CN6)]4- is outer orbital complex and paramagnetic with three unpaired electrons.d)[Mn(NO)3(CO)] is square planar and diamagnetic.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statements is correct?Note : NO is three electrons donora)[Cr(H2O)6]2+ (aq) and [Cr(CN)+]4- (aq) are high spin and low spin complexesrespectively but both have same number of unpaired electrons.b)[V(NH3)6]3+ is inner orbital complex and paramagnetic with two unpaired electrons.c)[Co(CN6)]4- is outer orbital complex and paramagnetic with three unpaired electrons.d)[Mn(NO)3(CO)] is square planar and diamagnetic.Correct answer is option 'B'. Can you explain this answer?.
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