Which of the following statements is correct?Note : NO is three electr...
Explanation:
Paramagnetism and diamagnetism are the two fundamental properties displayed by the coordination compounds, depending on the presence or absence of unpaired electrons.
a) [Cr(H2O)6]2+ (aq) and [Cr(CN)6]4- (aq) both are high spin and low spin complexes, respectively, but both have the same number of unpaired electrons.
- [Cr(H2O)6]2+ (aq) is a high spin complex with four unpaired electrons.
- [Cr(CN)6]4- (aq) is a low spin complex with no unpaired electrons.
b) [V(NH3)6]3+ is an inner orbital complex and paramagnetic with two unpaired electrons.
- [V(NH3)6]3+ has a d3 configuration, and it is an inner orbital complex because the electrons are first filled in the inner d orbitals and then in the outer d orbitals.
- The two unpaired electrons are present in the outer d orbitals, which gives rise to paramagnetism.
c) [Co(CN)6]4- is an outer orbital complex and paramagnetic with three unpaired electrons.
- [Co(CN)6]4- has a d6 configuration, and it is an outer orbital complex because the electrons are first filled in the outer d orbitals and then in the inner d orbitals.
- The three unpaired electrons are present in the outer d orbitals, which gives rise to paramagnetism.
d) [Mn(NO)3(CO)] is square planar and diamagnetic.
- [Mn(NO)3(CO)] has a d6 configuration, and it is square planar because the ligands are arranged in a plane around the central metal atom.
- The six electrons are paired up in the d orbitals, which gives rise to diamagnetism.
Therefore, option B is the correct answer.