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If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ?
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If two solution of strong acids of ph =2 and ph=4 be mixed In volume r...
Yrr isme intial volume kya le pata nahi chal raha ha...please check the question ????
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If two solution of strong acids of ph =2 and ph=4 be mixed In volume r...
Explanation:
Step 1: Calculate the concentration of H+ ions in the two solutions using pH.
- For pH = 2, [H+] = 10^(-2) = 0.01 M
- For pH = 4, [H+] = 10^(-4) = 0.0001 M
Step 2: Calculate the concentration of H+ ions in the resulting solution using the volume ratio.
Let the volume of the solution with pH 2 be V and the volume of the solution with pH 4 be zV.
- Total volume = V + zV = (1 + z)V
- Total concentration of H+ ions = (0.01 V) + (0.0001 zV) = 0.01V(1 + 0.001z)
Therefore, the concentration of H+ ions in the resulting solution is:
[H+] = (0.01V(1 + 0.001z))/(1 + z)V = 0.01/(1 + 0.001z)
Step 3: Use pH = -log[H+] to find the pH of the resulting solution.
pH = -log(0.01/(1 + 0.001z))
pH = -log(0.01) + log(1 + 0.001z)
pH = 2 + log(1 + 0.001z)
Step 4: Set the pH of the resulting solution to 2.75 and solve for z.
2.75 = 2 + log(1 + 0.001z)
0.75 = log(1 + 0.001z)
10^(0.75) = 1 + 0.001z
z = (10^(0.75) - 1)/0.001
z ≈ 421.7
Therefore, the volume ratio is 1:421.7.
Note: log 1.75 is not relevant to this problem.
Step 1: Calculate the concentration of H+ ions in the two solutions using pH.
- For pH = 2, [H+] = 10^(-2) = 0.01 M
- For pH = 4, [H+] = 10^(-4) = 0.0001 M
Step 2: Calculate the concentration of H+ ions in the resulting solution using the volume ratio.
Let the volume of the solution with pH 2 be V and the volume of the solution with pH 4 be zV.
- Total volume = V + zV = (1 + z)V
- Total concentration of H+ ions = (0.01 V) + (0.0001 zV) = 0.01V(1 + 0.001z)
Therefore, the concentration of H+ ions in the resulting solution is:
[H+] = (0.01V(1 + 0.001z))/(1 + z)V = 0.01/(1 + 0.001z)
Step 3: Use pH = -log[H+] to find the pH of the resulting solution.
pH = -log(0.01/(1 + 0.001z))
pH = -log(0.01) + log(1 + 0.001z)
pH = 2 + log(1 + 0.001z)
Step 4: Set the pH of the resulting solution to 2.75 and solve for z.
2.75 = 2 + log(1 + 0.001z)
0.75 = log(1 + 0.001z)
10^(0.75) = 1 + 0.001z
z = (10^(0.75) - 1)/0.001
z ≈ 421.7
Therefore, the volume ratio is 1:421.7.
Note: log 1.75 is not relevant to this problem.
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If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ?
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If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ?.
If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If two solution of strong acids of ph =2 and ph=4 be mixed In volume ratio 1:z the ph of resulting solution was found to be 2.75 then z is (log 1.75=0.25 ?.
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