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The type of intermolecular interaction present in n-Hexane and n-Octane is
- a)Vander wall forces of interaction
- b)Ion-dipole interaction
- c)Hydrogen bonding
- d)Dipole-dipole interaction
Correct answer is option 'A'. Can you explain this answer?
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The type of intermolecular interaction present in n-Hexane and n-Octan...
Both are Non Polar.
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The type of intermolecular interaction present in n-Hexane and n-Octan...
Intermolecular Interactions in n-Hexane and n-Octane
In organic chemistry, intermolecular interactions play a crucial role in determining the physical and chemical properties of compounds. These interactions arise due to the presence of different types of forces between molecules. The type of intermolecular interaction present in n-Hexane and n-Octane is Vander Waals forces of interaction.
Vander Waals Forces
Vander Waals forces are weak attractive forces that exist between all molecules, regardless of their polarity. These forces arise due to temporary fluctuations in the electron distribution within molecules, resulting in temporary partial positive and negative charges. Vander Waals forces can be further divided into three categories:
1. London Dispersion Forces: These forces are present in all molecules and are the result of temporary fluctuations in electron distribution. As electrons move around, they can create temporary dipoles, leading to an attractive force between neighboring molecules. London dispersion forces are the primary intermolecular forces in nonpolar molecules like n-Hexane and n-Octane.
2. Dipole-Dipole Interactions: These forces occur between molecules that have permanent dipoles. The positive end of one molecule is attracted to the negative end of another molecule, resulting in an overall attractive force. However, n-Hexane and n-Octane are nonpolar molecules, so dipole-dipole interactions are not significant.
3. Hydrogen Bonding: Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom (such as oxygen, nitrogen, or fluorine) and is attracted to another electronegative atom in a nearby molecule. However, n-Hexane and n-Octane do not contain hydrogen atoms bonded to highly electronegative atoms, so hydrogen bonding is not possible.
4. Ion-Dipole Interactions: Ion-dipole interactions involve the attraction between an ion and the partial charge on the end of a polar molecule. However, n-Hexane and n-Octane do not contain any ions, so ion-dipole interactions are not relevant.
Therefore, the primary intermolecular interaction present in n-Hexane and n-Octane is Vander Waals forces, specifically London dispersion forces. These forces arise due to temporary fluctuations in electron distribution, resulting in weak attractive forces between neighboring molecules.
In organic chemistry, intermolecular interactions play a crucial role in determining the physical and chemical properties of compounds. These interactions arise due to the presence of different types of forces between molecules. The type of intermolecular interaction present in n-Hexane and n-Octane is Vander Waals forces of interaction.
Vander Waals Forces
Vander Waals forces are weak attractive forces that exist between all molecules, regardless of their polarity. These forces arise due to temporary fluctuations in the electron distribution within molecules, resulting in temporary partial positive and negative charges. Vander Waals forces can be further divided into three categories:
1. London Dispersion Forces: These forces are present in all molecules and are the result of temporary fluctuations in electron distribution. As electrons move around, they can create temporary dipoles, leading to an attractive force between neighboring molecules. London dispersion forces are the primary intermolecular forces in nonpolar molecules like n-Hexane and n-Octane.
2. Dipole-Dipole Interactions: These forces occur between molecules that have permanent dipoles. The positive end of one molecule is attracted to the negative end of another molecule, resulting in an overall attractive force. However, n-Hexane and n-Octane are nonpolar molecules, so dipole-dipole interactions are not significant.
3. Hydrogen Bonding: Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom (such as oxygen, nitrogen, or fluorine) and is attracted to another electronegative atom in a nearby molecule. However, n-Hexane and n-Octane do not contain hydrogen atoms bonded to highly electronegative atoms, so hydrogen bonding is not possible.
4. Ion-Dipole Interactions: Ion-dipole interactions involve the attraction between an ion and the partial charge on the end of a polar molecule. However, n-Hexane and n-Octane do not contain any ions, so ion-dipole interactions are not relevant.
Therefore, the primary intermolecular interaction present in n-Hexane and n-Octane is Vander Waals forces, specifically London dispersion forces. These forces arise due to temporary fluctuations in electron distribution, resulting in weak attractive forces between neighboring molecules.
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The type of intermolecular interaction present in n-Hexane and n-Octane isa)Vander wall forces of interactionb)Ion-dipole interactionc)Hydrogen bondingd)Dipole-dipole interactionCorrect answer is option 'A'. Can you explain this answer?
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