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The equation of the normal to the ellipse  +  = 1 at the positive end of latus rectum is
  • a)
    x + ey + e2a = 0
  • b)
    x – ey – e3a = 0
  • c)
    x – ey – e2a = 0
  • d)
    None
Correct answer is option 'B'. Can you explain this answer?
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The equation of the normal to the ellipse+= 1 at the positive end of l...
 The positive end of latus rectum is
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The equation of the normal to the ellipse+= 1 at the positive end of l...
Hiii Tanmay.. so basically I am gonna tell u how to do it okay.. So First u may write the equation of tangent to an ellipse i.e y=mx+/-a(1+m^2)^1/2 now satisfy the point (ae,b^2/a) to this line get a value of m[u will get a quadratic in m] and put back to this... Hope u got this Regards
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The equation of the normal to the ellipse+= 1 at the positive end of latus rectum isa)x + ey + e2a = 0b)x –ey –e3a = 0c)x –ey –e2a = 0d)NoneCorrect answer is option 'B'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of the normal to the ellipse+= 1 at the positive end of latus rectum isa)x + ey + e2a = 0b)x –ey –e3a = 0c)x –ey –e2a = 0d)NoneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of the normal to the ellipse+= 1 at the positive end of latus rectum isa)x + ey + e2a = 0b)x –ey –e3a = 0c)x –ey –e2a = 0d)NoneCorrect answer is option 'B'. Can you explain this answer?.
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