The equation of trajectory of a projectile is y is equal to 10 x minus...
Calculation of Range of a Projectile
The given equation of the trajectory of a projectile is y = 10x - 5/9x2, where g = 10m/s2.
Finding the Maximum Height
To find the maximum height of the projectile, we need to differentiate the given equation of the trajectory with respect to x and equate it to zero.
dy/dx = 10 - (10/3)x
Equating it to zero, we get:
10 - (10/3)x = 0
x = 3
Substituting x = 3 in the given equation of the trajectory, we get:
y = 15
Therefore, the maximum height of the projectile is 15m.
Finding the Range
To find the range of the projectile, we need to find the values of x when y = 0. We can do this by solving the given equation of the trajectory for x when y = 0.
0 = 10x - 5/9x2
0 = x(10 - 5/9x)
x = 0 or x = 18/5
Therefore, the range of the projectile is 18/5m or 3.6m (approx).