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The equation of trajectory of a projectile is y is equal to 10 x minus 5 by 9 x square if we assume g is equal to 10 m per second then the range of projectile in meter is?
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The equation of trajectory of a projectile is y is equal to 10 x minus...
Calculation of Range of a Projectile


The given equation of the trajectory of a projectile is y = 10x - 5/9x2, where g = 10m/s2.


Finding the Maximum Height

To find the maximum height of the projectile, we need to differentiate the given equation of the trajectory with respect to x and equate it to zero.

dy/dx = 10 - (10/3)x

Equating it to zero, we get:

10 - (10/3)x = 0

x = 3

Substituting x = 3 in the given equation of the trajectory, we get:

y = 15

Therefore, the maximum height of the projectile is 15m.


Finding the Range

To find the range of the projectile, we need to find the values of x when y = 0. We can do this by solving the given equation of the trajectory for x when y = 0.

0 = 10x - 5/9x2

0 = x(10 - 5/9x)

x = 0 or x = 18/5

Therefore, the range of the projectile is 18/5m or 3.6m (approx).
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