Class 12 Exam > Class 12 Questions > For a cell given belowAg | Ag+|| Cu2+| Cu&mda...
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For a cell given below Ag | Ag+ || Cu2+ | Cu
— +
Ag+ + e- → Ag, Eº = x
Cu2+ +2e- → Cu, Eº = y
Eº cell is –
[AIEEE-2002]
- a)x + 2y
- b)2x + y
- c)y – x
- d)y – 2x
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
For a cell given belowAg | Ag+|| Cu2+| Cu— +Ag++ e- →Ag, E&...
The correct answer is Option C.
The left portion of the salt bridge(| |) is anode and the right portion of the salt bridge(| |) is cathode.
Since, Ag | Ag+ is half-cell oxidation and Cu2+ | Cu is half-cell reduction. Thus,
Eo cell = E cathode - E anode
= y - x
Eo cell = E cathode - E anode
= y - x
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For a cell given belowAg | Ag+|| Cu2+| Cu— +Ag++ e- →Ag, E&...
E• does not depend on molar concentration of reactants and products. Hence, the cell reaction is simply, eqⁿ2–eqⁿ1 = y–x
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For a cell given belowAg | Ag+|| Cu2+| Cu— +Ag++ e- →Ag, Eº = xCu2++2e- →Cu, Eº = yEº cell is – [AIEEE-2002]a)x + 2yb)2x + yc)y –xd)y –2xCorrect answer is option 'C'. Can you explain this answer?
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