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When during electrolysis of a solution of AgNO3 9650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be – 
[AIEEE-2003]
  • a)
    21.6 g
  • b)
    108 g 
  • c)
    1.08 g
  • d)
    10.8 g
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
When during electrolysis of a solution of AgNO39650 coulombs of charge...
The correct answer is Option D.
Ag+ + e- ---> Ag
So, no. of the moles of Ag = Q / F
                                           = 9650 / 96500
                                           =1 / 10 moles
∴ Mass of Ag produced :->
                                  (1/10) × 108
                                        = 10.8 g
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When during electrolysis of a solution of AgNO39650 coulombs of charge...
Here, no. of moles of electrons = Q/F = 9650/96500= 0.1 mole
Now,
 1 mole of AgNO will produce one mole of monovalent silver ion on dissociation.
Therefore,
.number of electrons involved will also be one mole for one mole of AgNO .
 Thus, 0.1 mole of silver will be produced by 0.1 mole of AgNO .
Since,
silver nitrate dissociates completely into Ag  and NO ion.
Hence,
mass of silver = no. of moles x molar mass= 0.1 x 108 = 10.8g
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When during electrolysis of a solution of AgNO39650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be –[AIEEE-2003]a)21.6 gb)108 gc)1.08 gd)10.8 gCorrect answer is option 'D'. Can you explain this answer?
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When during electrolysis of a solution of AgNO39650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be –[AIEEE-2003]a)21.6 gb)108 gc)1.08 gd)10.8 gCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When during electrolysis of a solution of AgNO39650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be –[AIEEE-2003]a)21.6 gb)108 gc)1.08 gd)10.8 gCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When during electrolysis of a solution of AgNO39650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be –[AIEEE-2003]a)21.6 gb)108 gc)1.08 gd)10.8 gCorrect answer is option 'D'. Can you explain this answer?.
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