A reaction was found to be second order with respect to the concentration of carbon monoxide. If the concentration of carbon monoxide is doubled, with everything else kept the same, the rate of reaction will -[AIEEE 2006]a)tripleb)increase by a factor of 4c)doubled)remain unchangedCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

As Given. r1= dx/dt = k [CO]^2
r2= k[2CO]^2
Thus, according to the rate law expression doubling the concentration of CO increase the rate law by a factor of 4

Answer

The correct answer is Option B.
The rate law expression is R=k[CO]2.
When concentration of CO is doubled, the rate law expression becomes ;
R′=k[2CO]2
=4k[CO]2
=4R.

Answer

The correct answer is Option B.
The rate law expression is R=k[CO]2.
When concentration of CO is doubled, the rate law expression becomes ;
R′=k[2CO]2
=4k[CO]2
=4R.

Answer

Increase by factor of 4

Answer

Second Order Reaction:
A second order reaction is a chemical reaction in which the rate of reaction is directly proportional to the square of the concentration of one of the reactants. Mathematically, it can be represented as:

Rate = k[A]^2

Where:
- Rate is the rate of reaction
- k is the rate constant
- [A] is the concentration of the reactant A

Doubling the Concentration:
Now, let's consider the given scenario where the concentration of carbon monoxide (CO) is doubled while everything else is kept the same.

Initially, let's assume the concentration of CO is [CO]0 and the rate of reaction is R0.

After doubling the concentration, the new concentration becomes 2[CO]0 and the new rate of reaction becomes R.

Effect on Rate of Reaction:
To determine the effect on the rate of reaction, we can compare the initial rate R0 with the new rate R.

According to the second order reaction rate equation, the rate of reaction is directly proportional to the square of the concentration of CO.

R0 = k([CO]0)^2

R = k(2[CO]0)^2
= 4k([CO]0)^2

Comparing R and R0, we can see that R is four times greater than R0.

Therefore, when the concentration of CO is doubled, the rate of reaction increases by a factor of 4.

Answer:
From the given options, the correct answer is option B, which states that the rate of reaction will increase by a factor of 4.

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