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 In a cell that utilises the reaction 
Zn(s) + 2H+ (aq)  Zn2+ (aq) + H2(g) 
addition of H2SO4 to cathode compartment, will–         
 [AIEEE-2004]
  • a)
    Lower the E and shift equilibrium to the left
  • b)
    Lower the E and shift equilibrium right
  • c)
    Increase the E and shift equilibrium to the right 
  • d)
    Increase the E and shift equilibrium to the left
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addit...
The correct answer is Option C.
Zn(s) +2H+ (aq) →Zn2+(aq)+H2(g)

So as we add sulphuric acid, conc. of hydrogen ion increases and equilibrium shifts to right.
Also according to the equation emf of the cell will be increased by adding acid.
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Community Answer
In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addit...
After addition of acid concentration of hydrogen ion increase eq shift towards right
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addition of H2SO4to cathode compartment, will– [AIEEE-2004]a)Lower the E and shift equilibrium to the leftb)Lower the E and shift equilibrium rightc)Increase the E and shift equilibrium to the rightd)Increase the E and shift equilibrium to the leftCorrect answer is option 'C'. Can you explain this answer?
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In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addition of H2SO4to cathode compartment, will– [AIEEE-2004]a)Lower the E and shift equilibrium to the leftb)Lower the E and shift equilibrium rightc)Increase the E and shift equilibrium to the rightd)Increase the E and shift equilibrium to the leftCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addition of H2SO4to cathode compartment, will– [AIEEE-2004]a)Lower the E and shift equilibrium to the leftb)Lower the E and shift equilibrium rightc)Increase the E and shift equilibrium to the rightd)Increase the E and shift equilibrium to the leftCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a cell that utilises the reactionZn(s)+ 2H+(aq)Zn2+(aq)+ H2(g)addition of H2SO4to cathode compartment, will– [AIEEE-2004]a)Lower the E and shift equilibrium to the leftb)Lower the E and shift equilibrium rightc)Increase the E and shift equilibrium to the rightd)Increase the E and shift equilibrium to the leftCorrect answer is option 'C'. Can you explain this answer?.
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