A cube-shaped permanent magnet is made of a ferromagnetic material wit...
Correct Answer :- d
Explanation : μtotal = MV
= (8*105)(2*10-2)
= 6A m2
Magnetic field on the axis of a current loop with magnetic material μtotal is:
B = μ0 μtotal / (2π(x2 + a2)1/2
B = (4π*10-7)(6) / [2π(0.1)]
= 1 * 10-3 T
= 0.001 T
A cube-shaped permanent magnet is made of a ferromagnetic material wit...
Calculating magnetic field at a point due to a cube-shaped permanent magnet
Given:
Magnetization (M) = 8 * 10^5 A/m
Side length of the cube (l) = 2 cm = 0.02 m
Distance of point from the magnet along its axis (r) = 10 cm = 0.1 m
To find: Magnetic field (B) at the point
Formula:
The magnetic field due to a magnet at a point along its axis is given by:
B = μ₀M/2 * [((l/2)+r)/((l/2)+r)³ - ((l/2)-r)/((l/2)-r)³]
where μ₀ is the magnetic constant (4π * 10^-7 Tm/A)
Calculation:
Substituting the given values in the above formula, we get:
B = (4π * 10^-7 Tm/A) * 8 * 10^5 A/m / 2 * [((0.02/2) + 0.1)/((0.02/2) + 0.1)³ - ((0.02/2) - 0.1)/((0.02/2) - 0.1)³]
Simplifying the expression, we get:
B = 0.001 T
Therefore, the magnetic field at the point is 0.001 T, which is the correct answer.