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The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2 (where (en) is ethylene diamine) are, respectively –
[AIEEE-2008]
- a)6 and +2
- b)4 and +2
- c)4 and +3
- d)6 and +3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The coordination number and the oxidation state of the element 'E&...
The correct answer is option D
The coordination number is the number of coordinate covalent bonds formed with a central metal atom. ligand en is a bidentate ligand that has two donor atoms in one molecule. So, when two en ligands attach to the central atom they will make four covalent coordinate bonds. Also, Oxalate (C2O4) is bidentate ligand making two coordinate covalent bonds at a time. Hence overall the coordination number of the element E is 4+2=6.
The oxidation number can be calculated by adding the charges of all the ligands and counter ions (ions present outside the central atom).
Let the oxidation state of element E be x.
Ligand en is neutral. Oxalate carries−2charge NO2 (counter ion) carries −1charge.
So, x + (2 × 0) + (−2) + (−1) = 0
x − 2 − 1 = 0
x = +3
The coordination number is the number of coordinate covalent bonds formed with a central metal atom. ligand en is a bidentate ligand that has two donor atoms in one molecule. So, when two en ligands attach to the central atom they will make four covalent coordinate bonds. Also, Oxalate (C2O4) is bidentate ligand making two coordinate covalent bonds at a time. Hence overall the coordination number of the element E is 4+2=6.
The oxidation number can be calculated by adding the charges of all the ligands and counter ions (ions present outside the central atom).
Let the oxidation state of element E be x.
Ligand en is neutral. Oxalate carries−2charge NO2 (counter ion) carries −1charge.
So, x + (2 × 0) + (−2) + (−1) = 0
x − 2 − 1 = 0
x = +3
Most Upvoted Answer
The coordination number and the oxidation state of the element 'E&...
The coordination number of the element E in the complex [E(en)2(C2O4)]NO2 is 6. This is because there are two ethylene diamine (en) ligands and one oxalate (C2O4) ligand, each of which has a coordination number of 2.
The oxidation state of the element E can be determined by looking at the overall charge of the complex. In this case, the complex has a charge of -1 because of the nitrite (NO2) ligand. The oxidation state of the ethylene diamine (en) ligand is 0, and the oxalate (C2O4) ligand has an oxidation state of -2.
To balance the charges, the element E must have an oxidation state of +1. This is because the oxidation state of the ethylene diamine (en) ligand is 0 and the oxalate (C2O4) ligand has an oxidation state of -2, meaning that the element E must have a +1 oxidation state to balance out the -1 charge of the nitrite (NO2) ligand.
The oxidation state of the element E can be determined by looking at the overall charge of the complex. In this case, the complex has a charge of -1 because of the nitrite (NO2) ligand. The oxidation state of the ethylene diamine (en) ligand is 0, and the oxalate (C2O4) ligand has an oxidation state of -2.
To balance the charges, the element E must have an oxidation state of +1. This is because the oxidation state of the ethylene diamine (en) ligand is 0 and the oxalate (C2O4) ligand has an oxidation state of -2, meaning that the element E must have a +1 oxidation state to balance out the -1 charge of the nitrite (NO2) ligand.
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The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer?
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The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer?.
The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer?.
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The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The coordination number and the oxidation state of the element 'E' in the complex [E(en)2(C2O4)] NO2(where (en) is ethylene diamine) are, respectively –[AIEEE-2008]a)6 and +2b)4 and +2c)4 and +3d)6 and +3Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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