A hydrocarbon (R) has six membered ring in which there is no unsaturat...
Explanation:
The given compound is a hydrocarbon with a six-membered ring. It has two alkyl groups attached to the ring, one with 3 carbon atoms and branching at the 1st carbon atom, and the other with 4 carbon atoms.
Step 1: Identify the longest carbon chain
- The larger alkyl group has a main chain of three carbon atoms, with the second carbon atom substituted.
- The smaller alkyl group has a chain of three carbon atoms, with branching at the first carbon atom.
Therefore, the longest carbon chain is three carbon atoms.
Step 2: Number the carbon atoms in the ring
- Start numbering from the carbon atom attached to the smaller alkyl group.
- Number the remaining carbon atoms in a clockwise or counterclockwise direction to get the lowest possible numbers for the substituents.
Step 3: Name the substituents
- The smaller alkyl group attached to the first carbon atom is a methyl group (1 carbon atom).
- The larger alkyl group attached to the second carbon atom is a propyl group (3 carbon atoms).
Step 4: Write the IUPAC name
- The IUPAC name is written in the format: substituent + parent chain + suffix.
- The substituents are named in alphabetical order, regardless of their position on the parent chain.
In this case, the IUPAC name is:
1-(1-Methylethyl)-2-(2-methylpropyl)cyclohexane
Conclusion:
Therefore, the correct IUPAC name of the compound (R) is 1-(1-Methylethyl)-2-(2-methylpropyl)cyclohexane, which is option 'C'.