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Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer?.

Solutions for Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Bond dissociation enthalpy of H2, Cl2 and HCl are 434 , 242 and 431 kJ mol–1 respectively.Enthalpy of formation of HCl is : [2008]a)93 kJ mol–1b)– 245 kJmol–1c)– 93 kJmol–1d)245 kJmol–1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.