If TP and TQ are two tangents to a circle with centre O so that angle ...
We know that the sum of angle made by two tangents joined by an exterior point and the angle made at the centre of the circle is equal to 180 degrees
So, Angle POQ + Angle PTQ = 180
110 + Angle PTQ = 180
Angle PTQ = 180- 110 = 70 degrees
View all questions of this testIf TP and TQ are two tangents to a circle with centre O so that angle ...
We know that the sum of angle made by two tangents joined by an exterior point and the angle made at the centre of the circle is equal to 180 degrees
So, Angle POQ + Angle PTQ = 180
110 + Angle PTQ = 180
Angle PTQ = 180- 110 = 70 degrees
If TP and TQ are two tangents to a circle with centre O so that angle ...
•••it's too easy
look angle POQ is getting divide according to the draw it means
angle POT and angle TOQ= 1/2 of angle POQ
angle POT and angle TOQ= 110/2
angle POT and angle TOQ = 55
now let's see in ∆ TPO
we know that OPT = 90 ( radius is perpendicular to the tangent in a circle)
and also we have angle POT = 55
so in ∆ TPO
angle POT + angle OPT + angle PTO = 180
55 + 90 + angle PTO = 180
angle PTO = 180 - 145
angle PTO = 35
now we know angle PTQ = 2× angle PTO
angle PTQ = 2× 35
angle PTQ = 70 ans •••••