**Explanation:**

In a normal human cell, there are 46 chromosomes, which means there are 23 pairs of chromosomes. Each chromosome is composed of a DNA molecule that carries genetic information. Therefore, the number of nuclear DNA molecules in a human cell is equal to the number of chromosomes, which is 46.

**a) Metaphase of Mitosis:**
During metaphase of mitosis, the chromosomes line up along the equatorial plane of the cell. At this stage, each chromosome consists of two identical sister chromatids, which are joined together at the centromere. Since there are 46 chromosomes in a human cell, there are a total of 46 pairs of sister chromatids, resulting in a total of 92 nuclear DNA molecules.

**b) Metaphase I of Meiosis:**
During metaphase I of meiosis, homologous chromosomes pair up and align along the equatorial plane of the cell. Each homologous pair consists of two sister chromatids. Since there are 23 pairs of homologous chromosomes in a human cell, there are a total of 23 pairs of sister chromatids, resulting in a total of 46 nuclear DNA molecules.

**c) Anaphase I of Meiosis:**
During anaphase I of meiosis, the homologous chromosomes separate and move towards opposite poles of the cell. Each chromosome still consists of two sister chromatids. Therefore, there are still 23 pairs of sister chromatids, resulting in a total of 46 nuclear DNA molecules.

**d) Metaphase II of Meiosis:**
During metaphase II of meiosis, the sister chromatids align along the equatorial plane of the cell. Since the homologous chromosomes have already separated in the previous anaphase I, each chromosome now consists of a single chromatid. Therefore, there are 46 individual chromosomes, resulting in a total of 46 nuclear DNA molecules.

Hence, the correct answer is option 'A, B, C' as all these stages involve the alignment and separation of chromosomes, resulting in the presence of 92 nuclear DNA molecules in a normal human cell.