Find the equation of the line whose intercepts on X and Y-axes are a2a...
Consider the given points. (a2,0) and (0,b2)
We know that the equation of the line which is passing through the points
y−y1 =[ (y2−y1) / (x2−x1)] (x−x1)
So, y−0 = b2−0/0-a2(x-a2)
-ya2 - b2x = -b2a2
xb2 +ya2 = b2a2
View all questions of this testFind the equation of the line whose intercepts on X and Y-axes are a2a...
Consider the given points. (a2,0) and (0,b2)
We know that the equation of the line which is passing through the points
y−y1 =[ (y2−y1) / (x2−x1)] (x−x1)
So, y−0 = b2−0/0-a2(x-a2)
-ya2 - b2x = -b2a2
xb2 +ya2 = b2a2
Find the equation of the line whose intercepts on X and Y-axes are a2a...
Understanding Intercepts on Axes
To find the equation of a line based on its intercepts on the X and Y axes, we denote:
- The X-intercept as a2
- The Y-intercept as b2
These intercepts mean that the line crosses the X-axis at (a2, 0) and the Y-axis at (0, b2).
Equation of the Line Formulation
The general formula for a line based on its intercepts is given by:
- x/a + y/b = 1
Substituting a = a2 and b = b2 gives the equation:
- x/a2 + y/b2 = 1
To convert this into a more standard form, we can rearrange it:
- b2x + a2y = a2b2
This is the desired equation of the line.
Identifying the Correct Option
Now let's look at the provided options:
a) bx + ay = ab
b) b2x + a2b2y = a2
c) b2a2x + a2y = b2
d) b2x + a2y = a2b2
The derived equation b2x + a2y = a2b2 matches option 'D'.
Conclusion
Thus, the correct answer to the question is option 'D', which clearly represents the equation of a line with specified intercepts on the X and Y axes. This understanding is crucial for solving similar problems in the JEE examination and helps in grasping the concept of linear equations in two dimensions.