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A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.?
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A particle A of mass 10/7 kg is moving in the positive x direction . I...
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A particle A of mass 10/7 kg is moving in the positive x direction . I...
And its initial velocity is 4 m/s. The particle is subjected to a constant force of 8 N in the positive x direction.
To find the position of the particle at any given time, we can use the equation of motion:
F = ma
where F is the force acting on the particle, m is the mass of the particle, and a is the acceleration of the particle.
Given that the force acting on the particle is 8 N and the mass of the particle is 10/7 kg, we can calculate the acceleration:
a = F/m
= 8 / (10/7)
= 8 * (7/10)
= 5.6 m/s^2
Now, to find the position of the particle at any given time, we can use the equation of motion:
x = x0 + v0t + (1/2)at^2
where x is the position of the particle at time t, x0 is the initial position of the particle, v0 is the initial velocity of the particle, a is the acceleration of the particle, and t is the time.
Given that the initial position of the particle is x0 = 0, the initial velocity of the particle is v0 = 4 m/s, the acceleration of the particle is a = 5.6 m/s^2, and the time is t, we can calculate the position of the particle at any given time:
x = 0 + (4 * t) + (1/2) * (5.6 * t^2)
Simplifying the equation:
x = 4t + 2.8t^2
Therefore, the position of the particle at any given time t is given by the equation x = 4t + 2.8t^2.
To find the position of the particle at any given time, we can use the equation of motion:
F = ma
where F is the force acting on the particle, m is the mass of the particle, and a is the acceleration of the particle.
Given that the force acting on the particle is 8 N and the mass of the particle is 10/7 kg, we can calculate the acceleration:
a = F/m
= 8 / (10/7)
= 8 * (7/10)
= 5.6 m/s^2
Now, to find the position of the particle at any given time, we can use the equation of motion:
x = x0 + v0t + (1/2)at^2
where x is the position of the particle at time t, x0 is the initial position of the particle, v0 is the initial velocity of the particle, a is the acceleration of the particle, and t is the time.
Given that the initial position of the particle is x0 = 0, the initial velocity of the particle is v0 = 4 m/s, the acceleration of the particle is a = 5.6 m/s^2, and the time is t, we can calculate the position of the particle at any given time:
x = 0 + (4 * t) + (1/2) * (5.6 * t^2)
Simplifying the equation:
x = 4t + 2.8t^2
Therefore, the position of the particle at any given time t is given by the equation x = 4t + 2.8t^2.
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A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.?
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A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.?.
A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.?.
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A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.?, a detailed solution for A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? has been provided alongside types of A particle A of mass 10/7 kg is moving in the positive x direction . Its initial position is x=0&initial velocity 1 m/s . The velocity at x=10m . Use the graph of power v/s position (in m) at x=0&power =2 watt , at x=10 &power=4 watt.? theory, EduRev gives you an
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