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Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire is
- a)6 mm2
- b)8 mm2
- c)10 mm2
- d)12 mm2
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Two similar wires under the same load yield elongations of 0.1 mm and ...
According to the equation Y =F*L/A*delta L=we have given two elongation of length and one area and find area A2 so A*delta L =constant A1*L1=A2*L 2 put value 4*0.1=A2*0.05=8mm answer
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Two similar wires under the same load yield elongations of 0.1 mm and ...
Given:
Elongation of the first wire = 0.1 mm
Elongation of the second wire = 0.05 mm
Cross-sectional area of the first wire = 4 mm^2
Let's assume the cross-sectional area of the second wire is A.
Using Hooke's Law, we know that the strain in a wire is directly proportional to the stress applied to it. Therefore, we can write:
Strain1/Strain2 = Stress1/Stress2
The stress applied to a wire is given by:
Stress = Force/Area
Since the wires are under the same load, the force applied to both wires is the same. Therefore, we can write:
Stress1/Stress2 = Area2/Area1
To find the area of the second wire (A), we can rearrange the equation as follows:
Area2 = (Stress2/Stress1) * Area1
Now, let's calculate the stress for each wire. The stress is given by:
Stress = Force/Area
Since the wires are under the same load, the force applied is the same for both wires. Therefore, the stress is inversely proportional to the cross-sectional area. We can write:
Stress1/Stress2 = Area2/Area1
Since the elongation is directly proportional to the stress, we can write:
Elongation1/Elongation2 = Stress1/Stress2
Substituting the given values:
0.1 mm / 0.05 mm = Area2 / 4 mm^2
Simplifying the equation:
2 = Area2 / 4 mm^2
Multiplying both sides by 4 mm^2:
8 mm^2 = Area2
Therefore, the area of cross-section of the second wire is 8 mm^2, which corresponds to option B.
Elongation of the first wire = 0.1 mm
Elongation of the second wire = 0.05 mm
Cross-sectional area of the first wire = 4 mm^2
Let's assume the cross-sectional area of the second wire is A.
Using Hooke's Law, we know that the strain in a wire is directly proportional to the stress applied to it. Therefore, we can write:
Strain1/Strain2 = Stress1/Stress2
The stress applied to a wire is given by:
Stress = Force/Area
Since the wires are under the same load, the force applied to both wires is the same. Therefore, we can write:
Stress1/Stress2 = Area2/Area1
To find the area of the second wire (A), we can rearrange the equation as follows:
Area2 = (Stress2/Stress1) * Area1
Now, let's calculate the stress for each wire. The stress is given by:
Stress = Force/Area
Since the wires are under the same load, the force applied is the same for both wires. Therefore, the stress is inversely proportional to the cross-sectional area. We can write:
Stress1/Stress2 = Area2/Area1
Since the elongation is directly proportional to the stress, we can write:
Elongation1/Elongation2 = Stress1/Stress2
Substituting the given values:
0.1 mm / 0.05 mm = Area2 / 4 mm^2
Simplifying the equation:
2 = Area2 / 4 mm^2
Multiplying both sides by 4 mm^2:
8 mm^2 = Area2
Therefore, the area of cross-section of the second wire is 8 mm^2, which corresponds to option B.
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Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer?
Question Description
Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer?.
Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer?.
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Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Two similar wires under the same load yield elongations of 0.1 mm and 0.05 mm respectively. If the area of cross-section of the first wire is 4 mm2, then the area of cross-section of the second wire isa)6 mm2b)8 mm2c)10 mm2d)12 mm2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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